The circumference of the outer edge of the path around the pool is 113.04 ft.
<h3>
What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
To know more about circumference click the link given below.
brainly.com/question/5023328
Answer:
Below
Step-by-step explanation:
Discount: 40% of $159 = $63.60
Price you pay: $159 - $63.60 = $95.40
From 17 x 17. to simplify, (1/2(17)(17) x tan A)
C is your answer. Because 8 times 1.75$ = $14.00 and 5 times 1.25= $6.25. So $14.00+ $6.25 = $20.25
Answer:
a linear equation in x and y
Step-by-step explanation:
The given equation is a linear equation (all variables to the first power) relating the variables x and y. There are an infinite number of values of x and y that will satisfy this equation.
When graphed on an x-y plane, those solution values will fall on a straight line with a slope of 2. It will cross the y-axis at y=32, and the x-axis at x=-16.