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3 years ago

Please help me thanks

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

8 0

Answer: I think its Consine

Step-by-step explanation:

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Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN

sashaice [31]

Answer:

The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

and (x2 , y2) are $x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}$

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ $x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}$

∵ $y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}$

∴ The coordinates of the midpoint are $(-2\frac{1}{2},4\frac{1}{2})$

* The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

8 0

3 years ago

Answer the questions about the following

djyliett [7]

Answer:

10×4+1-73

40+1-73

41-73

-32

4 0

3 years ago

Read 2 more answers

How many solutions does the equation 9x-3(x+8)=6x-24 have?

Neporo4naja [7]

I think the answer is C-No solutions

4 0

3 years ago

In the United States, there are 59 different species of mammals that are endangered,

jolli1 [7]

Given Information:

Number of endangered mammal species = 59

Number of endangered bird species = 75

Number of endangered fish species = 68

Required Information:

Probability of either a mammal or a fish = ?

Answer:

P(mammal or fish) = 127/202 = 0.6287 = 62.87%

Step-by-step explanation:

We want to randomly select one animal and find out the probability of either a mammal or a fish.

The total number of endangered species of animals is given by

Total animals = mammal species + bird species + fish species

Total animals = 59 + 75 + 68 = 202

The probability of selecting a endangered mammal is

P(mammal) = no. of endangered mammal/total no. of endangered animals

P(mammal) = 59/202

The probability of selecting a endangered fish is

P(fish) = no. of endangered fish/total no. of endangered animals

P(fish) = 68/202

Finally, the probability of selecting either a mammal or a fish is

P(mammal or fish) = 59/202 + 68/202

P(mammal or fish) = 127/202

P(mammal or fish) = 0.6287

P(mammal or fish) = 62.87%

8 0

3 years ago

Jim and Sarah invited seven friends over for dinner. If each friend brought one guest how many people will be at the dinner excl

Vanyuwa [196]

16 people would be at the dinner because Jim and Sarah invited 7 friends and each friend brought 1 guest, so you do 7*2=14 and the 14 + Jim and Sarah=16 people.

7 0

3 years ago