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Savatey [412]
3 years ago
8

A survey asked 60 students if they play an instrument and if they are in band.

Mathematics
2 answers:
miv72 [106K]3 years ago
5 0
A (I used process of elimination)

B is incorrect it says the total # of people not in a band is 35 but the description says only 30 aren’t in a band

C is incorrect because it says the total # of people that play an instrument is 30 but the description says 35 students play an instrument

D is incorrect because the way the graph is set up doesn’t make sense (ex. How can someone qualify for “not being in band but play an instrument” but also qualify for “in band and play instrument”

atroni [7]3 years ago
4 0
<h3>Answer:  Choice A</h3>

=======================================================

Explanation:

The table headers will look like choice A or choice C. Notice that we have simple yes or no questions along either the row or column labels; also, the labels are consistent. Choice B can be ruled out because the labels aren't consistent (or don't match up). Choice D is overcomplicated so it can be ruled out also.

We're told that 35 students play an instrument. That means 35 goes at the end of the "plays instrument" row, in the "total" column.

This is enough to see that choice A is the final answer

Furthermore, 30 students are in a band. So we have "30" at the bottom of the "band" column, and in the "total" row. The same applies to the 30 people not in band.

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Kiran’s backpack weighs 3 pounds less than Clare’s backpack. Clare’s backpack weighs 14 pounds. How much does Kiran’s backpack w
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a construction company charges $15 per hour for debris removal , plus a one -time fee for the use of the trash dumpster.the tota
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Let h be the numbers of hours, f be the one-time fee and c the cost charged. The equation is

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Solve each inequality, and then drag the correct solution graph to the inequality.
Nesterboy [21]

The correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

4(9x-18)>3(8x+12)

First, clear the brackets,

36x-72>24x+36

Then, collect like terms

36x-24x>36+72\\12x >108

Now divide both sides by 12

\frac{12x}{12} > \frac{108}{12}

∴ x > 9

For the second inequality

-\frac{1}{3}(12x+6) \geq -2x +14

First, clear the fraction by multiplying both sides by 3

3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)

-1(12x+6) \geq -6x +42

Now, open the bracket

-12x-6 \geq -6x +42

Collect like terms

-6 -42\geq -6x +12x

-48\geq 6x

Divide both sides by 6

\frac{-48}{6} \geq \frac{6x}{6}

-8\geq x

∴ x\leq  -8

For the third inequality,

1.6(x+8)\geq 38.4

First, clear the brackets

1.6x + 12.8\geq 38.4

Collect likes terms

1.6x \geq 38.4-12.8

1.6x \geq 25.6

Divide both sides by 1.6

\frac{1.6x}{1.6}\geq  \frac{25.6}{1.6}

∴ x \geq  16

Let the graphs be A, B and C from left to right

The first graph (A) shows x\leq  -8 and this matches the 2nd inequality

The second graph (B) shows x \geq  16 and this matches the 3rd inequality

The third graph (C) shows x > 9 and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

4(9x-18)>3(8x+12)  →  C

-\frac{1}{3}(12x+6) \geq -2x +14  → A

1.6(x+8)\geq 38.4  →  B

Learn more here: brainly.com/question/17448505

8 0
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