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Brums [2.3K]
4 years ago
11

1.3(-7.5m - 3.3) + 0.8m = 2.07 - 3.4m

Mathematics
1 answer:
____ [38]4 years ago
4 0

Answer:

m = -1.145946

You might be interested in
Abel and Cedric will share a total of $180. Abel will receive half as much as Cedric. What amount. in dollars, will Cedric recei
babymother [125]

Answer:

Abel receives $60, and Cedric receives $120

Step-by-step explanation:

Let Abel's share = A

Let Cedric's share = C

we are given the following

A + C = 180  - - - - - (1)   (Abel and Cedric will share a total of $180)

A = \frac{C}{2}\ - - - - - - - (2) (Abel will receive half as much as Cedric. )

from equation 2:

A = \frac{C}{2}\\ C = 2A\ - - - - - - (3)

putting this value of C in eqn (3) into eqn (1)

A + (2A) = 180

3A = 180

∴ A = 180 ÷ 3 = 60

to find C, let us replace the value of A in eqn (3) with 60

C = 2A - - - - (3)

C = 2 × 60

C = 120

Therefore, Abel receives $60, and Cedric receives $120

5 0
3 years ago
The area of a rectangular pool is given by the trinomial 2y^2-y-3. What are the possible dimensions of the pool? Use factoring.
RSB [31]

Answer:

(2y−3)(y+1) hope this helps!

7 0
3 years ago
How many different 6-digit numbers can be formed by arranging the digits in 332345?
Feliz [49]

Answer- 120

Solution-

There are digits to be arranged,they are {3,3,2,3,4,5}. And from those ,3 digits are repeated .

so the total number of distinct number that can be formed = \frac{6!}{3!} = \frac{720}{6} = <em>120</em><em> </em>(ans)


7 0
4 years ago
Pls hurry I’m being timed
Ksju [112]
I believe the answer is “A”
7 0
3 years ago
Read 2 more answers
The surface of a table to be built will be in the shape shown below. The distance from the center of the shape to the center of
Cloud [144]
Part a : you could draw a line from each corner to the middle
This would give you 7 triangles in total

Part b : area of one triangle : 4.5*7.8 = 35.1 / 2 = 17.55in <-- area of 1 triangle

Part c : so if there are 7 triangles and the area of 1 triangle is 17.55, you would do:
7 * 17.55 = 122.85

5 0
4 years ago
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