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Diano4ka-milaya [45]
3 years ago
6

Rhombus ADEF is inscribed in △ABC such that the vertices D, E, and F lie on the sides AB , BC , and AC respectively. Find the si

de of the rhombus if AB=7 cm, BC=5 cm, and AC=8 cm.

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0
<h3>Answer:</h3>

3 11/15 cm

<h3>Step-by-step explanation:</h3>

AE is the angle bisector of ∠A, so divides the sides of the triangle into a proportion:

... BE:CE = BA:CA = 7:8

Then ...

... BE:BC = 7 : (7+8) = 7:15

ΔDBE ~ ΔABC, so DE = 7/15 × AC

... DE = 7/15 × 8 cm = (56/15) cm

... DE = 3 11/15 cm

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