In the above word problem, If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles, Quarter 8-inch tiles will cover the same area as one 2-inches.
<h3>What is the justification for the above?</h3>
Note that the area of the one 2-inch tiles is given as:
A1 = 4in²
The area of the quarter 8-inch tiles is:
A2 = 1/4 x 8 x 8
A2 = 16inch²
Divide both areas
A2/A1= 16/4
= 4
This implies she'll need four 2-inch tiles to cover the same amount of space as a quarter 8-inch tile.
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Full Question:
A homeowner is deciding on the size of tiles to use to fully tile a rectangular wall in her bathroom that is 80 inches by 40 inches. The tiles are squares and come in three side lengths: 8 inches, 4 inches, and 2 inches. State if you agree with each statement about the tiles. Explain your reasoning.
If she chooses the 8-inch tiles, she will need a quarter as many tiles as she would with 2-inch tiles,
Answer:
Find the sum of the series
∑(4x−5)
such that
1≤x≤7
.
answer is 77
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
We know a number is an expression when it is:
1) NOT greater/ less than something else
2) NOT equal/ not equal to something else
The only answer choice that satisfies the above is A.
Answer:
y=0x+0
Step-by-step explanation:
The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
<h3>How to find the area of a trapezoid and rhombus?</h3>
The given pattern consists of rhombus and trapezoids
The formula for calculating the area of rhombus is expressed as:
A = pq/2
Area of trapezoid = 0.5(a+b)h
Given the following
height = 2in
a = 2in
b = 3in
Ara of rhombus = 1(4)/2 = 2 square inches
Area of the trapezoid = 0.5(2+3) * 2
Area of the trapezoid = 5 square inches
Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096
