If you understand what is linear pair, you can see the same in triangle also. A linear pair is a pair of adjacent, supplementary angles. Adjacentmeans next to each other, and supplementary means that the measures of the two angles add up to equal 180 degrees.
Answer: No solution
Step-by-step explanation:
2m+4p=22
6m+12p=66
First, to choose one variable to simplified, I choose to find 1st equations in m form.
2m+4p=22
2m=22-4p [Subtract 4p from both side]
m=22/2 - 4/2p [Divide 2 on both side to find m]
m= 11 - 2p
6m+12p=66
6(11-2p)+12p=66 [Plug in the 11-2p in to m,according to the 1st equation]
66-12p+12p=66
The -12p has cancel with 12p, so it means that there is no solution
we can pretty much split the middle part into two trapezoids. Check the picture below.
so we really have one trapezoid and one square, each twice, so simply let's get the area of the trapezoid and sum it up with the area of the square, twice, and that's the area of the shape.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{\textit{parallel sides}}{bases}\\[-0.5em] \hrulefill\\ h=5\\ a=3\\ b=7 \end{cases}\implies A=\cfrac{5(3+7)}{2}\implies A=25 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{sum of areas}}{[25+(3\cdot 3)]}\cdot \stackrel{twice}{2}\implies [34]2\implies \underset{in^2}{68}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7B%5Ctextit%7Bparallel%20sides%7D%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D5%5C%5C%20a%3D3%5C%5C%20b%3D7%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B5%283%2B7%29%7D%7B2%7D%5Cimplies%20A%3D25%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20areas%7D%7D%7B%5B25%2B%283%5Ccdot%203%29%5D%7D%5Ccdot%20%5Cstackrel%7Btwice%7D%7B2%7D%5Cimplies%20%5B34%5D2%5Cimplies%20%5Cunderset%7Bin%5E2%7D%7B68%7D)
If you get confused by logarithms, here's an easier way to think about this problem: What power of 2 equals 128? Well, we know 2^3 = 8, then 2^4 must equal 16. Doubling every times, we get 2^5 = 32, 2^6 = 64 and 2^7 = 128. So, the value of log₂128 is 7.
Answer:
f(x) = 3 if x ≤ -2
= 1 if x > -2 ⇒ attached figure
Step-by-step explanation:
* Lets explain how to answer the question
- For the part of the graph on the left side (2nd quadrant)
- There is a horizontal line start from x = -∞ and stop at x = -2
- The end of the line is black dot means x = -2 belongs to the function
- The horizontal line drawn at y = 3
∴ The equation of the horizontal line is y = 3
∴ The function represents this part of graph is y = 3 if x ≤ -2
- The other part of the graph is also horizontal line start from
x = -2 to x = ∞
- The end of the line is white dot means x = -2 does not belong
to the function
- The horizontal line drawn at y = 1
∴ The equation of the horizontal line is y = 1
∴ The function represents this part of graph is y = 1 if x > -2
* f(x) = 3 if x ≤ -2
= 1 if x > -2
- The answer is attached