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Scrat [10]
3 years ago
14

HELP PLEASE ILL BE GIVING OUT 13 POINTS TO WHOEVER ANSWERS EARLY! PLEASE QUICKLY HELP

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0

<em>Answer:</em>

D)(6(-3)/9)

<em>Step-by-step explanation:</em>

<em>                  -1</em>

<em>Simplify   ——</em>

<em>                  3 </em>

<em>       -1</em>

<em>6 • ——</em>

<em>       3 </em>

<em>-2</em>

<em>If this was helpful, please mark brainliest. Have a beautiful day!</em>

<em />

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Given: AB ≅ BC , m∠MOC = 135° OM − angle bisector of ∠AOB Prove: ∠ABO ≅ ∠CBO
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Answer:

See explanation

Step-by-step explanation:

1. Angles AOM and MOC are supplementry angles. If m∠MOC = 135°, then

m∠AOM = 180° - 135° = 45°

2. OM − angle bisector of ∠AOB, then

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3. Now

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4. Since m∠BOC = 90°, BO is perpendicular to AC.

5. Consider isosceles triangle ABC (because AB ≅ BC). BO is the height drawn to the base, so it is an angle B bisector too, thus

∠ABO ≅ ∠CBO

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