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Bingel [31]
3 years ago
14

Suppose that a pregnancy test kit, while tested on women, produces 95% true positive and 90% true negative. Suppose that 7% of w

omen are pregnant. What is the probability that a randomly selected woman who is teted positive, is actually pregnant?
Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

0.5885

Step-by-step explanation:

The possible ways for a test to be positive are:

- Woman is pregnant & true positive

- Woman is not pregnant & false positive

The probability of a positive is:

P(+) = 0.07*0.95+(1-0.07)*(1-0.95)\\P(+)=0.113

Therefore, the probability that a woman is actually pregnant given that she tested positive is:

P(P|+) = \frac{0.95*0.07}{0.113}\\P(P|+) = 0.5885

The probability is 0.5885

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weqwewe [10]

Answer:

50²yards

Step-by-step explanation:

Cut the shape into 2 peices. The square has a length of 6yd and base of 8yd. bh=48².The little triangle has a base of 4yd and a length of 6yd. bh/2=12².

48 plus 12 = 50yd²

5 0
2 years ago
What’s the correct answer for this question?
Bogdan [553]

Answer:

D

Step-by-step explanation:

Izan can use the slope formula to show that the slope of KL and MN are equal.

4 0
3 years ago
A 50 foot rope weighing a total of 32 lbs extended over a cliff that is 35 feet to the ground. A large 8 pound bucket with 19 ga
larisa86 [58]

Answer:

A function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is W=16(50-x)+(19-\frac{x}{5})(8.3)x and  the work to get the bucket to the top of the cliff is 3726 foot-lbs

Step-by-step explanation:

Work done to lift the rope by distance x feet:

W_1=32(\frac{50-x}{2})

Work done to lift the bucket by distance x feet:

W_2=(19-\frac{x}{5})(8.3)x

On reaching top 7 gallons of water spilled out so , on going up by x feet \frac{7x}{35}=\frac{x}{5} gallons of water spilled out.

a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground:

W=16(50-x)+(19-\frac{x}{5})(8.3)x

Now the work to get the bucket to the top of the cliff i.e. x =35

W=16(50-35)+(19-\frac{35}{5})(8.3)(35)

W=3726

Hence, a function that gives the work required in foot-lbs to lift the bucket up x feet from the ground is W=16(50-x)+(19-\frac{x}{5})(8.3)x and  the work to get the bucket to the top of the cliff is 3726 foot-lbs

5 0
3 years ago
3. find the domain and range of <br>a) 3x-2y+7=0<br>i think in y-intercept form it is y=3/2x + 7/2
bekas [8.4K]
3x-2y+7=0\\\\The\ slope-intercept\ form:\\\\2y=3x+7\ \ \ \ \ /:2\\\\y=\frac{3}{2}x+\frac{7}{2}\\\\The\ domain:x\in\mathbb{R}\\\\The\ range:y\in\mathbb{R}

3 0
3 years ago
If x &lt; 5, then which of the following must be true? - x &lt; 5 - x &gt; -5 - x &gt; 5 - x &lt; -5
Nat2105 [25]

Answer:

-x > -5

Step-by-step explanation:

Let's start with a positive number less than 5.

4<5

likewise when applied to -x> -5

-4>-5

4 0
3 years ago
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