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lesya [120]
3 years ago
12

Restaurateur Denny Valentine is evaluating two sites, Raymondville and Rosenberg, for his next restaurant. He wants to prove tha

t Raymondville residents (population 1) dine out more often than Rosenberg residents (population 2). Denny commissions a market survey to test this hypothesis. The market researcher used a random sample of X families from each suburb, and reported the following:
1 = X times per month and 2 = X times per month. Assume that σ1 = 2 and σ2 = 3. With α = .01, the appropriate decision is:_________
Mathematics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

Step-by-step explanation:

From the information given:

let \mu_1 be the men of the population 1 (Raymondville) and \mu_2 be the mean of the population 2 (Rosenberg).

Here the Restaurateur wants to prove that Raymondville residents dine out more often than Rosenberg residents.

i.e \mu_1 > \mu _2

The null hypothesis and alternative hypothesis:

H_o : \mu_1 \le \mu_2 \\ \\  H_a: \mu_1 > \mu_2

H_o : \mu_1 \le \mu_2\  \ vs \  \  H_a: \mu_1 > \mu_2 \implies \text{upper tailed test}

The shows that this test is one-tailed with the rejection area on the right side.

The appropriate decision: is to reject \mathbf{H_o} if the test statistics is greater than the critical value)

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Answer:

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Step-by-step explanation:

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Answer:

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s(av) =  \frac{∆x}{∆t}  \\

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s(av) =  \frac{183}{3}  \\

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Answer:

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\sf Quadratic \ Equation : \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a}

Knowing This:

<u>solve for b</u>

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