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Luden [163]
2 years ago
13

16.11 ÷ 99 19.6 ÷ 20 0.9 ÷ 11 50.8 ÷ 45 0.1414 ÷ 2 0.213 ÷ 31

Mathematics
1 answer:
ANEK [815]2 years ago
4 0
BEFORE YOU USE THE ANSWERS! I USED CALCULATOR AND IT TOLD ME THIS SO IM NOT SO SURE IF IM CORRECT!!
1: 0.16272727272
2: 0.98
3: 0.08181818181
4: 1.12888888889
5: 0.0707
6: 0.00687096774
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The least common denominator of the rational numbers x^2-y^2/(x^2-8x+15) and y^2/15(x^2-6x+9) is
Mashutka [201]

Answer:

15(x - 5)(x - 3)²

Step-by-step explanation:

factor both denominators and see what you need to do to make them equal...

(x² - y²)/[(x - 5)(x - 3)]           y²/[15(x - 3)(x - 3)]

the first denominator has (x - 5)(x - 3)          

the second denominator has 15(x - 3)(x - 3),

the least common denominator between them would be

15(x - 5)(x -3)(x - 3)     or  15(x - 5)(x - 3)²

7 0
3 years ago
Is 1.15 a rational number
iragen [17]

Answer:

No

Step-by-step explanation:

The given number is 1.15. Here, the digits after the decimal are terminating, so the given number is rational, NOT irrational. Thus, 1.15 is NOT an irrational number.

6 0
3 years ago
A pair of boots costing $299 is marked down 45%.
Paraphin [41]

Answer: 164.45

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions
Mkey [24]

Answer:

Width = 18 inches

Length = 59 inches

Step-by-step explanation:

The length of a rectangle is five more than triple the width. If the perimeter is 154 inches, what are the dimensions

Perimeter of a rectangle = 2L + 2W

The length of a rectangle is five more than triple the width.

L = Length = 5 + 3W

W = Width

If the perimeter is 154 inches, what are the dimensions

Hence,

154 = 2L + 2W

154 = 2(5 + 3W ) + 2W

154 = 10 + 6W + 2W

Collect like terms

154 - 10 = 8W

144 = 8W

W = 144/8

W = 18 inches

Length = 5 + 3W

Length = 5 + 3(18)

Length = 5 + 54

Length = 59 inches

8 0
3 years ago
Find the amplitude and the equation of the midline of the periodic function.
Masja [62]

Answer:

Option B. Amplitude =3 midline is y =2.

Step-by-step explanation:

In the graph attached we have to find the amplitude and midline of the periodic function.

Amplitude of the periodic function = (Distance between two extreme points on y asxis)/2

=  (5-(-1))/2 = (5+1)/2 =6/2 =3.

Since amplitude of this function is 3 and by definition amplitude of any periodic function is the distance between the midline and the extreme point of wave on one side.

Therefore midline of the wave function is y=2 from which measurement of the amplitude is 3.

6 0
3 years ago
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