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Travka [436]
3 years ago
6

The radius of a circular rug is 5 feet. How much ribbing will you need to buy to go around the

Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

For this case we must find the perimeter of the circular carpet.

By definition, the perimeter of a circle is given by:

P = 2 \pi * r

Where:

r: It is the radius of the circle

According to the statement we have:

r = 5 \ ft

Substituting:

P = 2 * 3.14 * 5\\P = 2 * 3.14 * 5\\P = 31.4 \ ft

So, you need31.4 \ ft

Answer:

31.4 \ ft

leonid [27]3 years ago
5 0

The length around the rug is the circumference.

The formula is C = 2 x PI x r

C = 2 x 3.14 x 5 = 31.4 feet

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What is the square root of <br> X of the power of 2 -1 =80?
zepelin [54]

Answer:

x=6561

Step-by-step explanation:

We can solve this equation for x to get

\sqrt{x} -1=80\\\\\sqrt{x} =81\\x=(81)^2\\\\x=6561

5 0
3 years ago
What is the value of x?<br> 12 units<br> 18<br> 15 units<br> 20 units<br> 24 units
Ierofanga [76]

Answer:

Step-by-step explanation:

Question

What is the value of x?

12 units

Answer:

Step-by-step explanation:18

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24 units

5 0
3 years ago
Read 2 more answers
a positive number is 5 times less than another positive number. Six times the lesser number plus 3 times the greater is 3. Find
IgorLugansk [536]
<h2>Greetings!</h2>

Answer:

One number is \frac{5}{7} and the other number is \frac{1}{7}

Step-by-step explanation:

Let x be the smaller number and y be the bigger number.

x = x

y = 5x

6x + 3y = 3

6x + (3 * 5x) = 3

6x + 15x = 3

(÷3)

2x + 5x = 1

7x = 1

x = \frac{1}{7}

6x + 3y = 3

6(\frac{1}{7}) + 3y = 3

\frac{6}{7} + 3y = 3

3y = 3 - \frac{6}{7}

3y = \frac{15}{7}

Divide both sides by 3 to get 1y:

y = \frac{5}{7}

So one number is \frac{5}{7} and the other number is \frac{1}{7}


<h2>Hope this helps!</h2>
5 0
2 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
Lmk ASAP please
Licemer1 [7]

Answer:

Step-by-step explanation:

i wear more supreme then a hype beast only blew no green dont excite me i can make a girl out your wifie

4 0
2 years ago
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