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soldi70 [24.7K]
3 years ago
5

Gena attached a dog ramp to her sofa, which allows her oldest dog to easily climb onto a seat cushion. The ramp is 55 inches lon

g. The top of the seat cushion is 28 inches above the floor.
What is the distance from the base of the ramp to the base of the sofa? Enter your answer, rounded to the nearest tenth.
Mathematics
1 answer:
N76 [4]3 years ago
3 0
If we were to view the ramp from its side, the profile would resemble a right triangle with a 90 degree angle where the sofa meets the floor.

In this case, the two legs of the right triangle are 55 inches and 28 inches, and we looking for the length of the hypotenuse.

We can use Pythagorean Theorem which states:

a^2 + b^2 = c^2

 where a and b are the legs, and c is the hypotenuse.

55^2 + 28^2 = c^2

3025 + 784 = c^2

c^2 = 3809

c =  \sqrt{3809}

c = 61.717 inches

To the nearest tenth, the answer is 61.7 inches.
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Bill can hit a bucket of 323 gold balls in 17 hours.
yanalaym [24]
It is important to clearly understand all the important information's already given in the question. Based on those details the answer to the question can be easily determined.
In 17 hours the number of golf balls hit by Bill = 323
Then
In 1 hour the number of golf balls hit by Bill = (323/17) * 1
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So
The number of golf balls hit by Bill in 23 hours = 23 * 19
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So 437 balls will be hit by Bill in 23 hours. I hope the procedure is clear enough for you to understand. This procedure will help you to solve similar problems in future without requiring any outside help.
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3 years ago
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Can y’all help me on question 40?!
Anastaziya [24]

Answer:

t = 3c

Step-by-step explanation:

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2 years ago
La siguiente tabla presenta las frecuencias absolutas y relativas de las distintas caras de un dado cuando se simulan 300 lanzam
noname [10]

La opinión correcta es la de Camila que argumenta que la frecuencia relativa de la cara con el #6 será un valor cercano a 0,166.

<h3>Qué es la frecuencia relativa?</h3>

La frecuencia relativa es un término matemático que se utiliza en la estadística para referirse al número de veces que un evento se repite durante un experimento.

Por otra parte, es necesario aclara que la frecuencia relativa no se modifica en gran medida si se aumenta el número de veces de una prueba, debido a que la probabilidad de ocurrencia de este evento va a ser la misma.

De acuerdo a lo anterior, Camila tiene razón debido a que considera que el valor de la frecuencia relativa no se modifica en gran medida entre 300 o 600 lanzamientos de los dados.

Nota: Esta pregunta está incompleta porque no está la tabla. No obstante, la puedo responder basado en mi conocimiento previo.

Aprenda más sobre probabilidad en: brainly.com/question/16019390

6 0
2 years ago
Four times the square of a number is thirty-six"
natka813 [3]
Well first do 36 divided by 4, which is 9, then square root 9 to make it 3, so your answer should be 3
5 0
3 years ago
Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi
boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required  

\hat p=\frac{63}{200}=0.315 represent the estimated proportion of people that have experienced bullying

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{63}{200}=0.315 represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

And replacing into the confidence interval formula we got:  

0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.261  

0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.369  

And the 90% confidence interval would be given (0.261;0.369).  

We are confident at 90% that the true proportion of people that they were planning to pursue a graduate degree is between (0.261;0.369).  

lower limit =0.261

upper limit =0.369

5 0
3 years ago
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