Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Answer:
12
Step-by-step explanation:
idk but please just mark me brainliest
Answer:
The answer is C
2.640 and 10,560
Step-by-step explanation:
264 * 410 = (264 * 400) + (264 * 10) = 105,600 + 2640 = 2.640 and 10,560
You should get the app "photomath" that will help out alot!!!