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Lelechka [254]
3 years ago
13

Betty and Andrea have been solving systems of equations with one polynomial function of degree two and one linear function. Bett

y says there must always be two solutions, and Andrea says there will no solution. Using complete sentences, explain how Betty can be correct, how Andrea can be correct, and how they both can be wrong.
Mathematics
2 answers:
olganol [36]3 years ago
4 0
A system of equations with one polynomial function of degree two and one linear function will have two solutions when the line intersects the parabola at two points.

A system of equations with one polynomial function of degree two and one linear function will have no solution when the line does not intersects the parabola.

A system of equations with one polynomial function of degree two and one linear function will have one solution when the line intersects the parabola at one point.

shtirl [24]3 years ago
4 0
This system of equations will have two solutions when there are two points that the line intersects with. It will have no solution when the line does not intersect the parabola. It will have only one solution when the line only intersects at one point. Hope this answers the question.
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If you know the answer could you help me on it
Kipish [7]

Answer:

The answer is B because the numbers in the geometric sequence are being multiplied by 2.


6 0
3 years ago
Aisha runs a tutoring business. With Plan 1, students may choose to pay $26 per hour. With Plan 2, they may follow the plan show
Finger [1]

Answer:

$20 dollars and $10 dollars per hour

Step-by-step explanation:

the line starts at 20 and it escalates by 10 ( 10,20,30,40,50,ect)

i just had a question like this and i'm in middle school, i tried to look for the answer on here but no one answered so when i took time to answer the problem i got it right on the first try.. anyway i hope this helps .!

3 0
3 years ago
Leticia charges 8$ per hour to babysit. She babysat Friday night for 4 hours ,and then she babysat again on saturday.She earned
BaLLatris [955]
Leticia babysat on Saturday for 5 hours. She already babysat for 4 hours which makes it (8 x 4) =$32 But she earned $72 so the rest $40 / 8 =5 hours 
4 0
3 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
Lowest common multiple of 12,18,56
Ira Lisetskai [31]

Step-by-step explanation:

12 = 2 × 2 × 3

18 = 2 × 3 × 3

56 = 2 ×2 × 2 × 7

Now

Common factor = 2

Remaining factor = 2 × 3 × 2 × 3 × 7

LCM = RF × CF

= 504

hence the lCM of 12 , 18 and 56 is 504...

...

8 0
2 years ago
Read 2 more answers
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