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3 years ago

Which of the symbols correctly relates the two numbers? 100 ? 20

Mathematics

2 answers:

Yanka [14]3 years ago

6 0

I hope it's may be 100>20

rewona [7]3 years ago

3 0

We can see that 100 is greater than 20.

So we insert the greater than symbol.

And the greater than symbol is >, note the two strokes faces the bigger number

100 > 20

I hope this explains it.

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artcher [175]

Answer:

u=92

Step-by-step explanation:

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2 years ago

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Fiesta28 [93]

Answer:

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Step-by-step explanation:

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3 years ago

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Ivahew [28]

Answer:

b = 44 feet 

Step-by-step explanation:

BY Pythagorus theorem :-

=》

$55 {}^{2} = 33 {}^{2} + b {}^{2}$

=》

$3025 = b {}^{2} + 1089$

=》

$b {}^{2} = 3025 - 1089$

=》

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2 years ago

A 2-column table has 4 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1. The second column is label

JulijaS [17]

The growth factor of the exponential function represented by the table is 5.

The correct option is c.

<h3>What is the growth factor of the exponential function?</h3>

The growth factor of the exponential function is the ratio of the two consecutive terms (y-values).

The growth factor of the exponential function is given by;

$\rm Growth\ factor=\dfrac{y(x_2)}{y(x_1)}\\\\$

As per given, we have a table;

x y

-2 0.004

-1 0.02

0 0.1

1 0.5

The value $\rm x_2$ is -2 and $\rm x_1$ is -1.

Therefore,

the growth factor of the exponential function represented by the table would be :

$\rm Growth\ factor=\dfrac{y(x_2)}{y(x_1)}\\\ \rm Growth\ factor=\dfrac{y(-1)}{y(-2)}\\\\\rm Growth\ factor=\dfrac{0.02}{0.004}\\\\ \rm Growth\ factor=5$

Hence, the growth factor of the exponential function represented by the table is 5.

To know more about the Growth factor click the link given below.

brainly.com/question/985668

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2 years ago

Two cables support a 800-lb weight, as shown. Find the tension in each cable.

jeka94

Answer:

892 lb (right)
653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

Rcos(45°) +Lcos(75°) = 800

Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

= 800sin(75°)/sin(120°) ≈ 892 . . . pounds

L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

(right, left) = w/sin(α+β)×(sin(β), sin(α))

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2 years ago