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2 years ago

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A triangle has an angle that measures 95°. The other two angles are in a ratio of 6:11. What are the measures of those two angle

s?

1 answer:

Vlad [161]2 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

The sum of two numbers is 84. The square of the first number is 6 more than the second number.

DerKrebs [107]

The system of equations to find the value of x, the first number, and y, the second number are;

<em>y = -x + 84</em>

<em>y = x² + 6</em>

<h3>System of equation</h3>

The system of equation are equations that contains more than two equation and unknown.

Let the two unknown numbers x and y

If the sum of two numbers is 84, hence;

x +y = 84

y = -x + 84

If the square of the first number is 6 more than the second number, hence;

x² = y + 6

Substitute equation 2 into 2 to have:

x² = y + 6

x² = (-x+84) + 6

x² = -x+84 + 6

x² +x+84 + 6 = 0

x² +x + 90 = 0

Hence the system of equations to find the value of x, the first number, and y, the second number are;

<em>y = -x + 84</em>

<em>y = x² + 6</em>

Learn more on system of equation here; brainly.com/question/12861087

#SPJ1

4 0

2 years ago

Put the following statements into order to prove that if 3n+4 is even then n is even. Put N next to the 3 statements that should

Alinara [238K]

Answer: 7, 2, 1, 5, 6, 4, 8

Step-by-step explanation:

1. Then, 3n+4=3(2k+1)+4=6k+7=2(3k+3)+1.

2. By definition of odd, there exists integer k such that n=2k+1.

N 3. Thus, if n is odd then 3n+4 is odd or by contradiction, if 3n+4 is even then n is even, .

4. Therefore, by definition of odd, 3n+4 is odd.

5. Since k is an integer, t =3k+3 is also an integer.

6. Thus, there exists an integer t such that 3n+4=2t+1.

7. Suppose n is odd.

8. Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even, .

N 9. Suppose 3n+4 is even.

N 10. By definition of odd, n=2k+1.

Right order:

7. Suppose n is odd.

2. By definition of odd, there exists integer k such that n = 2k+1.

1. Then, 3n+4 = 3(2k+1)+4 = 6k+7 = 2(3k+3)+1.

5. Since k is an integer, t = 3k+3 is also an integer.

6. Thus, there exists an integer t such that 3n+4 = 2t+1.

4. Therefore, by definition of odd, 3n+4 is odd.

8. Thus, if n is odd then 3n+4 is odd or by contraposition, if 3n+4 is even then n is even.

4 0

3 years ago

Which table represents a linear function?

Rus_ich [418]

Linear means that the y values go up in a fixed increment, k.
In the first one, you see that 3+4=7, 7+4=11, and so on, so you can immediately tell that it's linear.

The second one goes 3+5=8, then 8+7=15, then 15+6=21, which aren't the same numbers.

The third increases and decreases, so it's not linear.

The fourth goes 3+6=9, then 9+18=27, which you can immediately tell is not linear.

Therefore, the only linear table would be the first one.

3 0

3 years ago

Read 2 more answers

(a) If you toss 10 coins, what percent of the time will you get the three most likely macrostates (6 heads and 4 tails, 5 heads

FromTheMoon [43]

This question is incomplete, the microstates table is left out which will be uploaded along this answer;

Answer:

a) the required is 65.6%

b) the required time is 4.2666 hrs

Step-by-step explanation:

using the microstates from the table in the diagram;

a)

the percent times the above any of the above microstates occurs is;

% (6 heads and 4 tails, 5 heads and 5 tails, 4 heads and 6 tails)

= ((210 + 252 + 210)/1024) × 100

= 0.6562 × 100

= 65.6%

Therefore the required is 65.6%

b)

the probability of getting 10 heads and 0 tail or 0 tail head and 10 tails is;

p( 10H, 0T or 0H, 10T = 2/1024

= 1/512

so on average, it will take 512 trails or at a rate of 2 trials/min, 256 mim in hours;

(256 min) ( 1h/60min) = 4.2666 hrs

Therefore the required time is 4.2666 hrs

8 0

2 years ago

Express the function f(x) =3x^2-6x-18 in the form a(x + h)^2=k, where a, h and k are constants.Hence state the :

ololo11 [35]

Answer:

The minimum value of f(x) is -21 and it occurs at x = 1

Step-by-step explanation:

f(x) =3x^2-6x-18

Factor out the greatest common factor out of the first two terms

f(x) =3(x^2-2x)-18

Complete the square

-2x/2 =-1 (-1)^2 = 1

Add 1 (But remember the 3 out front so we are really adding 3 so we need to subtract 3 to remain balanced)

f(x) = 3(x^2 -2x+1) -3 -18

f(x) = 3(x-1)^2 -21

This is vertex form

f(x) = a(x-h)^2 +k where (h,k) is the vertex and a is a constant

The vertex is (1,-21)

Since a > 0 this opens upward and the vertex is a minimum

The minimum value of f(x) is -21 and it occurs at x = 1

6 0

3 years ago