All categories

3 years ago

BRAINLIEST IF CORRECT PLEASE SHOW WORK:)

2 answers:

8 0

The answer would be d 1 1/18 because you have to convert the 1/6 to 3/18 and 2/9 to 4/18 so 4/18 minus 3/18 is 1/18 and 8 minus 7 is 1 so it is 1 1/18

Licemer1 [7]3 years ago

4 0

First of all, you will want to change the fraction to have the same denominator.

The common factor for 9 and 6 is 18. (9x2=18 and 6x3=18)
Then, you multiply the numerator by the factor you got in the first step, which is 2 and 3, respectively.
So the new fractions are $\frac{4}{18}$ and 7 $\frac{3}{18}$

The next step is to simply subtract the mixed numbers!
$8 \frac{4}{18}$ - $\frac{3}{18}$ = 1 1/18

The answer would be <span>D: 1 1/18!</span>

You might be interested in

The owner of BobCats R Us paid his personal MasterCard bill using a company check. What is the correct entry to record the trans

charle [14.2K]

Credit cash; debit withdrawals

7 0

3 years ago

Find h. 10 cm h h = ✓ [?] cm .... 6 cm

Evgesh-ka [11]

Answer:

h²= G²- R²

h² = 10²-6²

h²= 100 - 36

h²= 64

h = √64

.............

8 0

3 years ago

Helpppp please asappp

34kurt

Answer: i may be wrong but is it 4?

5 0

3 years ago

5 points

jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11$

5 0

3 years ago

I need a tutor who can answer more than 1 question.if not im sorry i have to end the session

nirvana33 [79]

Part A.

The area of a triangle is given by the product of its base and the height relative to that base.

Since these triangles have the same base b and same height h, they have the same area.

Part B.

The area of a rectangle or parallelogram is given by the product of base and height. Since these figures have the same base and height, they have the same area.

Part C.

These figures have different shapes, so we can't affirm that they have the same area.

Part D.

The height shown in the image is not the height relative to side b, therefore we can't affirm that the triangles have the same area.

4 0

1 year ago