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ValentinkaMS [17]

3 years ago

10

Nina can ride her bike 63,360 feet in 3,400 seconds, and Sophia can ride her bike 10 miles in 1 hour. What is Nina's rate in mil

es per hour if there are 5,280 feet in a mile?

1 answer:

BlackZzzverrR [31]3 years ago

8 0

3400/3600 to change seconds to hours = 0.94 hours
63360 / 5280 = 12 miles

12 miles / 0.94 hours = 12.77 miles/hour

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If two sides of one triangle are proportional to two sides of another and included angles are equal, then the triangles are simi

tiny-mole [99]

Yes the triangles are similar. It’s true

8 0

3 years ago

A standard container measures 2.4 m by 2.4 m by 6 m.

ella [17]

Answer:

34.56

Step-by-step explanation:

5 0

2 years ago

What segment is congruent to AC?<br> A. BD<br> B. BE<br> C. CE<br> D. none

Phoenix [80]

You can find the segment congruent to AC by finding another segment with the same length. So first, you need to find the length of AC.

C - A = AC
0 - (-6) = AC Cancel out the double negative
0 + 6 = AC
6 = AC

Now, find another segment that also has a length of 6.

D - B = BD
2 - (-2) = BD Cancel out the double negative
2 + 2 = BD
4 = BD
4 ≠ 6

E - B = BE
4 - (-2) = BE Cancel out the double negative
4 + 2 = BE
6 = BE
6 = 6

So, the segment congruent to AC is B. BE .

8 0

3 years ago

Im going to die dumb please help

vova2212 [387]

Answer:

im thinking it's experimental or sample space but go with your mindset

Step-by-step explanation:

im thinking experimental since he made a prediction before. and im also thinking of sample space because he made a outcome if he rolled a regular dice 120 times basically that's a sample space so yah.

8 0

2 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

8 0

3 years ago