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andrezito [222]
3 years ago
9

Expand. Your answer should be a polynomial in standard form. (3c + 2)(c^2-6c-4)

Mathematics
1 answer:
evablogger [386]3 years ago
3 0

Answer:

After expanding the polynomial (3c + 2)(c^2-6c-4) we get  3c^3-16c^2-24c-8

Step-by-step explanation:

We need to expand the polynomial (3c + 2)(c^2-6c-4)

Multiply the terms:

(3c + 2)(c^2-6c-4)\\=3c(c^2-6c-4)+2(c^2-6c-4)\\=3c^3-18c^2-12c+2c^2-12c-8\\=3c^3-18c^2+2c^2-12c-12c-8\\=3c^3-16c^2-24c-8

So, after expanding the polynomial (3c + 2)(c^2-6c-4) we get  3c^3-16c^2-24c-8

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Answer:

0.30

Step-by-step explanation:

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Probability of stopping at atleast one of the two signals:

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Stopping at both signals :

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P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

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Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

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3 years ago
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Answer:

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Step-by-step explanation:

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sergiy2304 [10]
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barxatty [35]

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Step-by-step explanation:

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