This diagram shows a right cylinder. Recall that the area of

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

8 0

Answer:

A=Pi x radius x height+2 x pi x radius^2

Step-by-step explanation:

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Transversal cuts parallel lines and at points X and Y respectively. The point nearest to C is X, and the point nearest to D is Y

hammer [34]

Answer: The answer is (B) ∠SYD.

Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.

We are given four angles, out of which one should be chosen which is congruent to ∠CXP.

The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.

For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.

Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.

Thus, we have

∠CXP ≅ ∠SYD.

So, option (B) is correct.

5 0

3 years ago

If c=25 and B=75 degrees, find a. Round to the nearest tenth.

worty [1.4K]

Answer:

a=6.9

Step-by-step explanation:

Since you know that C is a right angle, you can use the Law of Sines to find a. The first step is to find the size of the angle A, which is 180-74-90=16. Now, you set up a ratio that involves 3 knowns and one unknown to get $\frac{\sin(90^\circ)}{25} = \frac{\sin(16^\circ)}{a}$ , which after cross multiplying yields $a=\sin(16^\circ)\cdot25\approx 6.9$ . PM me if you have any questions?