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agasfer [191]
3 years ago
6

Kelly is reading a 288 page book

Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

4 days

Step-by-step explanation:

4*192/8, after solving that you get 96. Add 96 to the amount she already read which is 192. 192+96=288.

Hope this helped :)

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Interpret bar graphs
Volgvan

Answer:

Reading bar graphs (multi-step) In a bar graph each bar represents a number. The following bar graph shows the number of seconds that different rides last at the fair. We can tell how long each ride lasts by matching the bar for that ride to the number it lines up with on the left.

Here is an example:

3 0
3 years ago
9 pencils cost $7.74.Which equation would help determine the cost of 6 pencils?
Dima020 [189]

Answer:

The equation is x= (7.74 /9) 6  

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

If 9 pencils cost $7.74, we have to divide the total cost ($7.74) by the number of pencils (9) to obtain the price of 1 pencil.

Now that we have the price of 1 pencil, to obtain the cost of 6 of them we simply multiply the result by six.

Mathematically speaking:

x= (7.74 /9) 6  

Where:

x = Cost of 6 pencils in $

Solving:

x = 0.86 x 6 = $5.16

8 0
3 years ago
Read 2 more answers
A car and a motor bike are priced at $23440. If the value of the car is four times the value of the motor bike, how much is the
LenKa [72]

x + y = 23440

x = 4y

y = ?

23440 / 5 = 4688

y = $4688

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%7Ba%20%7D%5E%7B2%7D%20%20%2B%208a%20%2B%2015%20%3D%200" id="TexFormula1" title=" {a }^{2}
NISA [10]

Answer:

a = - 5, a = - 3

Step-by-step explanation:

Given

a² + 8a + 15 = 0 ← in standard form

(a + 3)(a + 5) = 0 ← in factored form

Equate each factor to zero and solve for a

a + 3 = 0 ⇒ a = - 3

a + 5 = 0 ⇒ a = - 5

8 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
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