Answer:
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Step-by-step explanation:
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MATH 10550, EXAM 1 SOLUTIONS 1. If f(2) = 5, f(3) = 2, f(4) = 5, g(2 ...
Cutting her time by 50% means reducing her time by half. Half of 45 seconds is 22.5 seconds. Therefore, to make the team, she must run a lap in 22.5 seconds.
This is solved by setting up two equations and then using one to answer the other.
The first step (use what is given to set up the two separate equations)
We are looking for two numbers, let us call them X and Y.
We are told that X + Y = 59
We are also told that (9 more than) 9+ (4times the smaller number) 4Y is the bigger number X
Then we combine that into 9+4Y=X
so we now have two separate equations and we can use one to solve the other. Everywhere we have X in the first equation, we will fill in with the second equation
(9+4Y) +Y = 59 [then combine like terms]
9+5Y=59 [subtract 9 from both sides]
5Y=50 [divide both sides by 5 to isolate the Y]
Y=10 [now plug this into either equation to solve for X]
9+4(10)=X
9+40=X
<u><em>49=X and 10=Y</em></u>
<span>If 3x-1=11, then 2x=?
</span><span>
2x + x - 1 = 11
2x = -x +12</span>
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