Ask question

Ask question

All categories

3 years ago

8

Which of these relations is a function?

2 answers:

Vinvika [58]3 years ago

8 0

Answer:

top right

Step-by-step explanation:

ICE Princess25 [194]3 years ago

6 0

The one on the rope that is not a circle

You might be interested in

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago

A rectangle has a length of twenty one cm and a diagonal of twenty nine cm. How wide is the rectangle?

GuDViN [60]

The width of the rectangle become 20 cm.

According to the statement

we have to find the width of the rectangle.

So, For this purpose, we know that the

Rectangle is a parallelogram all of whose angles are right angles.

According to the information:

A rectangle has a length of 21 cm and a diagonal of 29 cm.

Here we use the this formula

d² = l² + w²

So, Substitute the values

29² = 21² + w²

841 = 441 + w²

Now, solve it then

w² = 400

Solve the square root then value becomes

w = 20 cm.

The width of the rectangle become 20 cm.

So, The width of the rectangle become 20 cm.

Learn more about Rectangle here

brainly.com/question/19819849

#SPJ9

3 0

1 year ago

Write an equation in slope intercept form of the line passing through (5,-4) and is perpendicular to a line whose equation is -2

Sergeu [11.5K]

Rearrange the given equation in slope intercept form
$y = \frac{3x - 1}{ - 2} \\ y = - \frac{3}{2} x + \frac{1}{2}$
slope of the required line is
$- \frac{1}{ - \frac{3}{2} } = \frac{2}{3}$
equation is given by
$y - y1 = m(x - x1) \\ y - - 4 = \frac{2}{3} (x - 5) \\ y + 4 = \frac{2x}{3} - \frac{10}{3} \\ y = \frac{2x}{3} - \frac{10}{3} - 4 \\ y = \frac{2}{3} x - \frac{22}{3}$

5 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

Solve the<br> equation:<br> -X/5 =q

Semenov [28]

Answer:

x = -5q

Step-by-step explanation:

-x/5 = q

-x = 5q

x = -5q

7 0

3 years ago

Read 2 more answers