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mafiozo [28]
4 years ago
11

Find a point e on cd such that the ratio of ce to cd is 1/8

Mathematics
1 answer:
harina [27]4 years ago
7 0
I hope this helps you

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How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
-BARSIC- [3]
The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

6 0
3 years ago
In the diagram, line x is parallel to line y,m21= 65°, and m27 = 55°. Stuart says that m212 = 60°. His reasoning is shown. Step
Artist 52 [7]

the second one I try so I hope that helps

5 0
3 years ago
Read 2 more answers
13.
dusya [7]

Answer:

B - x=5

Step-by-step explanation:

If y=25 is 250% more than y=10, so multiply 2 by 250% and you get 5

4 0
3 years ago
URGENT Enter the values for the highlighted variables that show how to subtract the rational expressions correctly: StartFractio
Marrrta [24]

The value of the highlighted variables ave been determined a =6, b= 2 ,c= 6 , d = 2  , e = 6 , f = 6, g =1

<h3>What is an Expression ?</h3>

An expression are mathematical statement consisting of variables , constants and mathematical operators .

The given expression is

\rm \dfrac{2}{x^2-36} - \dfrac{1}{x^2 +6x} = \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\\\= \dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{(x+6)(x+6)x}\\\\= \dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\= \dfrac{g}{x(x-6)}

a = 6

b= 2

c= 6

d = 2

e = 6

f = 6

g =1

Therefore the value of the highlighted variables ave been determined.

To know more about Expression

brainly.com/question/14083225

#SPJ1

3 0
2 years ago
Given that V=4/3πrcube , make r the subject of formula​
Sonbull [250]

Answer:

V =  \frac{4}{3} \pi {r}^{3}  \\  \\ 3V = 4\pi {r}^{3}  \\  {r}^{3}  =  \frac{3V}{4\pi}  \\  \\ r =  \sqrt[3]{ \frac{3V}{4\pi} }

6 0
3 years ago
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