How would this following triangle be classified
1 answer:
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Answer:
It is shifted c units to the left .
Step-by-step explanation:
In general, adding a constant c to the value of x shifts a graph c units to the left.
The graph of y = x + c is parallel to y = x, the y-intercept becomes (0, c) and the x-intercept becomes (-c, 0).
In the diagram below, the red line is the graph of y = x, and the blue line is the graph of y = x + 1.
<em><u>Question:</u></em>
What is an equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21
<em><u>Answer:</u></em>
<em><u>The equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21 is:</u></em>
<em><u>Solution:</u></em>
Given that line passes through the point (3,6) and is parallel to the line 4x-3y=21
<em><u>The equation of line in slope intercept form is given as:</u></em>
y = mx + c ------- eqn 1
Where, "m" is the slope and "c" is the y intercept
<em><u>Given equation is:</u></em>
4x - 3y = 21
Rearrange,
3y = 4x - 21
On comparing above equation with eqn 1,
We know that slopes of parallel lines are same
Therefore, slope of line parallel to the line 4x - 3y = 21 is 4/3
<em><u>Substitute m = 4/3 and (x, y) = (3, 6) in eqn 1</u></em>
<em><u>Substitute c = 2 and m = 4/3 in eqn 1</u></em>
Thus the equation of line is found