The more reasonable measurement of the distance between the tracks on a CD is 1.6 ⋅ 10^-3 mm. This is also equal to 0.0016mm. <span>1.6 ⋅ 10^3 mm is too large for a CD track</span>
Answer:
-3.25 Didn't see the whole paper so correct me if I'm wrong.
Step-by-step explanation:
−2.5+0.25+−1.25+−1.5
+1.25+0.5=-3.25
Answer:
15.6
Step-by-step explanation:
85 is the correct answer.
Answer:
x=√y+4 or x=−√y+4
Step-by-step explanation:
Step 1: Add 4 to both sides.
x2−4+4=y+4
x2=y+4
Step 2: Take square root.
x=√y+4 or x=−√y+4
