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Airida [17]
3 years ago
12

(-2ab^-5)(4a^-2b)^-2

Mathematics
1 answer:
enyata [817]3 years ago
4 0

Answer:

  -a^5/(8b^7)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

  a^-b = 1/a^b

__

  (-2ab^{-5})(4a^{-2}b)^{-2}=(-2ab^{-5})(4^{-2}a^{-2(-2)}b^{-2})\\\\=\dfrac{-2}{16}a^{1+4}b^{-5-2}=\boxed{-\dfrac{a^5}{8b^7}}

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Pls help me with this im stuck...
Sphinxa [80]

Answer:

100% of what it used to be

Step-by-step explanation:

8 0
3 years ago
Gummi bears come in twelve flavors, and you have one of each flavor. Suppose you split your gummi bears among three people (Adam
aliina [53]

Step-by-step explanation:

From the given gummi bear, the chance that Adam is selected for any draw is 1/3 as well as the chance he is not selected at any draw is 2/3.

a). The probability of Adam getting exactly three gummi bears = P(Adam gets selected at 3 draws and not selected at the remaining 9 draws)

= $ (\frac{1}{3})^3 (\frac{2}{3})^9 = \frac{2^9}{3^{12}} $

Now, the 3 draws where Adam gets selected can be any 3 out of 12 draws in $ {\overset{12}C}_3 $ = 220

Thus, probability of Adam getting three gummi bears = $ 220 \times \frac{2^9}{3^{12}} $

                                                                                                = 0.21186

b). Probability that Adam will get the three gummi bears given each person will received at the most 1 gummi bear

= P(of the remaining 9 draws after assigning one gummi bear to each one, Adam gets selected at 2 draws and not selected at 7 draws) = $ {\overset{9}C}_2 (\frac{1}{3})^2 (\frac{2}{3})^7 $

                                                                                               = 0.23411

c). Let X = Number of the gummi bears which Adam will get. Then, X = number of draws out of 12 draws Adam gets selected and X ~ B(12, 1/3). So,  Adam will get gummi bears= mean of B(12, 1/3) = 12 x (1/3) = 4

d). Let Y = Number of the gummi bears that Adam will get, given each person will received at the most 1 gummi bear Then, Y = number of draws Adam gets selected in the remaining 9 draws and Y ~ B(9, 1/3). So, the expected number of bears that Adam gets given each person received at least 1 gummi bear

= 1 + mean of B(9, 1/3) = 4

e). When every one gets atleast one gummi bear, the new sample size will be 9 and so we can say that there is a reduction in variance.

8 0
3 years ago
Solve for x. NEED ANSWER ASAP TYY SO MUCH IN ADVANCE
Serjik [45]

Answer:

x = 10√3

Step-by-step explanation:

Because of the right angles, we can use Pythagoras

30² - x² = y²  (a) Largest triangle

y² - 20² = h² (b) Medium triangle

substitute y² from (a) into (b)

30² - x² - 20² = h²

500 - x² = h²  (d)

x² - h² = (30 - 20)² (c) smallest triangle

substitute h² from (d) into (c)

x² - (500 - x²) = 100

2x² = 600

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4 0
3 years ago
Barbara wants to restore her '66 Mustang in 4 years. She puts $200 into an account every month that pays 4.5% interest, compound
Tcecarenko [31]

Answer:

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Step-by-step explanation:

We have been given that Barbara puts $200 into an account every month that pays 4.5% interest, compounded monthly.

To find the money in the account after 4 years, we will use future value formula.  

FV=R(\frac{1+\frac{r}{n})^{nt}-1}{\frac{r}{n}}), where,

R = Regular deposits,

r = Interest rate in decimal form

n = Number of times interest in compounded per year,

t = Time in years.

4.5\%=\frac{4.5}{100}=0.045

Substitute given values:

FV=\$200(\frac{1+\frac{0.045}{12})^{12*4}-1}{\frac{0.045}{12}})

FV=\$200(\frac{1+0.00375)^{48}-1}{0.00375})

FV=\$200(\frac{1.00375)^{48}-1}{0.00375})

FV=\$200(1.1968143774194609-1}{0.00375})

FV=\$200(0.1968143774194609}{0.00375})

FV=\$200(52.4838339785229066667)

FV=\$10496.76679570458133334

FV\approx \$10496.77

Therefore, there will be an amount of $10496.77 in the account after 4 years.

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Sonja [21]

Answer: y=2(x+2)

Step-by-step explanation:

The slope of the line is

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Using the point (-2, 0) to substitute into point-slope form, we get the equation to be \boxed{y=2(x+2)}

8 0
2 years ago
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