Part A you would just distribute your 3 to your X and your 5. After doing that you would get 3x+15+x=4x. Next you would combine like terms, meaning combine your x's together that is on the same side of your equal sign. So you would add 3x and x. When finished with that you would get, 4x+15=4x. You would then subtract your 4x on both sides of your equal sign. You then would get 15=0 which is no solution.
Part B you would distribute your 4 to your 1 and -x. After doing this your equation should then look like 4-4x=5x+8. Next you would try to get your like terms together. You would add 4x on both sides of your equal sign. Your equation should then look like 4=9x+8. Next you would subtract your 8 on both sides of the equal sign because your getting your terms together. Your equation should then look like, -4=9x. This answer would be one solution.
Part C you would combine your like terms, meaning add your 2x and x together to get your equation looking like, 3x+5=5+3x. You can tell just by looking at this equation it's going to be a infinite number of solutions.
Hope this helps! (:
Answer:The solution is in the attached file
Step-by-step explanation:
Answer:
See explanation.
(Before continuing reading, I took the base to be 3. Please tell me if you didn't want the base to be 3.)
Step-by-step explanation:
I assume 3 is suppose to be the base. Let's list some values that can be written as 3 to some integer.
3^0=1
3^1=3
3^2=9
3^3=27
3^4=81
3^5=243
......
I could have also did negative integer powers, but this is all I really need to convince you that log_3(28) is between 3 and 4.
log_3(28) means the value x such that 3^x=28.
Since 28 is between 27 and 81 in my list above, that means 3^x is between 3^3 and 3^4. This means that x is a value between 3 and 4.
The last 2 options are correct
Answer:
m = -8
Step-by-step explanation:
have a nice day! :)
