Answer:
Measure of angle 2 and angle 4 is 42°.
Step-by-step explanation:
From the figure attached,
m∠ABC = 42°
m(∠ABD) = 90°
m(∠ABD) = m(∠ABC) + m(∠DBC)
90° = 43° + m(∠DBC)
m(∠DBC) = 90 - 43 = 47°
Since ∠ABC ≅ ∠4 [Vertical angles]
m∠ABC = m∠4 = 42°
Since, m∠3 + m∠4 = 90° [Complimentary angles]
m∠3 + 42° = 90°
m∠3 = 90° - 42°
= 48°
Since, ∠5 ≅ ∠3 [Vertical angles]
m∠5 = m∠3 = 48°
m∠3 + m∠2 = 90° [given that m∠2 + m∠3 = 90°]
m∠2 + 48° = 90°
m∠2 = 90 - 48 = 42°
m∠3+ m∠4 = 90° [Since, ∠3 and ∠4 are the complimentary angles]
48° + m∠4 = 90°
m∠4 = 90 - 48 = 42°
Therefore, ∠2 and ∠4 measure 42°.
The answer is C. x=3 2(3)^3=54
2:1 is the ratio
- Rach :)
If 1/6 of the pan was left and there were 2 pieces left you just need to set 1/6 equal to 2/some number, this allows you to say that 1/6=2/x --> x/6=2-->x=12.
My explanation might be a little poor since this becomes fairly fundamental later on but hopefully it helps.