How many ounces of a 40% alcohol solution must be mixed with 16 ounces of a 45% alcohol solution to make a 44% alcohol solution

Mathematics

1 answer:

goblinko [34]3 years ago

3 0

I'm pretty sure it's 4 ounces so it makes up 1/5 of 40% alcohol and 4/5 of 45% alcohol

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A piece of wood is divided into two pieces in the ratio of 2:5. One piece is 10 cm long so how long is the other piece?

klio [65]

Answer:

The length of the pother piece of the wood is 25 cm.

Step-by-step explanation:

Let the length of a piece of wood is x such that the ratio of two pieces is 2:5. Two pieces are 2x and 5 x

Length of the first piece is 10 cm. It means, 2x = 10 i.e. x = 5

We have considered that the length of other piece is 5x. It means 5×5 = 25 cm.

Hence, the length of the pother piece of the wood is 25 cm

8 0

3 years ago

-6 <img src="https://tex.z-dn.net/?f=%20-%206%20%2B%203%20%5Ctimes%204%20-%2011" id="TexFormula1" title=" - 6 + 3 \times 4 -

ipn [44]

The answer is -5

Explanation:

-6 + 3 x 4 -11=
-6 + 12 -11=
+ 6 -11 = -5

4 0

3 years ago

Read 2 more answers

Look at the picture

Sonbull [250]

$\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \frac{9(|x-8|)}{9} < \frac{36}{9} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}$

$\underline{\boldsymbol{\sf{Answer}}}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }$

$\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \ correct \ option}} \ \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}$