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pickupchik [31]
1 year ago
7

The remains of an ancient ball court include a rectangular playing alley with a perimeter of about 18m. The length of the alley

is two times the width. Find the length and the width of the playing alley.The width is ? m and the length is ? m.
Mathematics
1 answer:
mariarad [96]1 year ago
3 0

Given:

Perimeter = 18 m

The formula for the perimeter of a rectangle is:

P=2l+2w

Where:

l = lenght

w = width

In this case, we have that:

l = 2w

Therefore, we substitute the values in the formula:

\begin{gathered} P=2l+2w \\ 18=2(2w)+2w \end{gathered}

And solve for w:

\begin{gathered} 18=4w+2w \\ 18=6w \\ \frac{18}{6}=\frac{6w}{6} \\ w=3 \end{gathered}

For the length:

l=2w=2(3)=6

Answer:

The width is 3 m

The length is 6 m

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