Answer:
any order where 2 is the last number in the sequence
Step-by-step explanation:
the ten-thousand place in 12,345 is 5.
ex: 3,8,9,5,2
5,9,8,3,2
8,9,5,3,2

The probability of getting 0 heads in 4 tosses (or equivalently, 4 tails) is

.
So the desired probability is
X=-2→y=7(6)^(-2+2)+1=7(6)^0+1=7(1)+1=7+1→y=8; (x,y)=(-2,8)
x=-5→y=7(6)^(-5+2)+1=7(6)^(-3)+1=7/6^3+1=7/216+1=0.0324+1→y=1.0324→(x,y)=(-5,1.0324)
Answer: Graph 3