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garik1379 [7]
3 years ago
9

198+727 rounding or compatible number

Mathematics
1 answer:
Roman55 [17]3 years ago
5 0
198+727=925 round it to 930.
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The gardening club at school is growing vegetables. The club has 300 square feet of planting beds. Cucumber plants require 6 squ
nadya68 [22]

<em>The question doesn't ask anything in particular, I will show the set of inequalities defined in the problem.</em>

Answer:

<em>System of inequalities:</em>

6c+4t\leq 300

c>0\\t > 0\\c+t\geq 60

Step-by-step explanation:

<u>Inequalities </u>

The express relations between expressions with a sign other than the equal sign. Common relationals are 'less than', 'greater than', 'not equal to', and many others.

The gardening club at school has 300 square feet of planting beds to plant cucumber and tomato. Each cucumber plant requires 6 square feet of growing space and each tomato plant requires 4 square feet of growing space. We know the total area cannot exceed 300 square feet, so

6c+4t\leq 300

Being c and t the number of cucumber and tomato plants respectively.

We also know the students want to plant some of each type of plant and have at least 60 plants. This lead us to more conditions

c>0\\t > 0\\c+t\geq 60

<em>Note: The set of inequalities shown is not enough to uniquely solve the problem. We need something to maximize or minimize to optimize c and t</em>

8 0
3 years ago
Solve for y: y+6=5(x-4)
lbvjy [14]

Answer:

Step-by-step explanation:

y+ 6= 5(x-4)

y + 6= 5x-20

   -6 .      -6

 ----------------

y= 5x-26

6 0
3 years ago
ANSWER ASAP!!!!
Korvikt [17]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
What is the value of i 97 – i?<br> –i<br> 0<br> –2i<br> i Superscript 96
Valentin [98]

<em>The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue</em>

Answer:

i^{97}-i=0

Step-by-step explanation:

<u>Powers of The Imaginary Unit</u>

The imaginary unit i is defined as

i=\sqrt{-1}

The first powers of i are

i^0=1

i^1=i

i^2=(\sqrt{-1})^2=-1

i^3=i.i^2=-i

i^4=i^2.i^2=1

And so on the cycle repeats every four numbers. To find the value of i^{96} we can find the remainder of 96/4=0. So i^{96}=i^0=1

The given expression is

i^{97}-i

Factoring

i(i^{96}-1)

Since i^{96}=1

=i(1-1)=0

The required value is 0

6 0
3 years ago
Read 2 more answers
Help I only have 15 minutes <br> -2 = 12x + 22
otez555 [7]

Answer:

x = -1

you're welcome bud.

3 0
3 years ago
Read 2 more answers
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