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2 years ago

8

The mean is A: Sometimes B: always C: never

1 answer:

podryga [215]2 years ago

6 0

I guess the mean is always

this question is not clear.

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For the data set: 22, 40, 21, 18, 47, 22, 19, what is the mode?

SashulF [63]

Hello!

Mode : $\fbox{it is the frequently occurIng value in the given set of observation}$

Given observations are :-

22,40,21,18,47,22,19

Now , mode = $\fbox{22}$

The answer is 22 as it appears two times in the given set of observations.

Hope this is clear :)
Have a good day:)

7 0

2 years ago

Solve The Linear Equation for the stated variable.

larisa [96]

Answer:

$m=\frac{g}{4c-3}$

Step-by-step explanation:

we have

$g=4cm-3m$

Solve for m

That means-----> isolate the variable m

Factor the variable m in the equation

$g=m[4c-3]$

Divide by (4c-3) both sides

$\frac{g}{4c-3}=m$

Rewrite

$m=\frac{g}{4c-3}$

6 0

3 years ago

Im struggling with this

xeze [42]

Answer:

i cant read it sorry

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What’s the domain and range

Softa [21]

Answer:

domain is x range is y

Step-by-step explanation:

4 0

3 years ago

Find the percentage of vacationers from<br> question 10 who spent between $1500<br> and $2000.

mars1129 [50]

Answer:

The percentage change of vacationers is 33.3 %

Step-by-step explanation:

Given as :

The old value of the vacationers = $ 1500

The new value of the vacationers = $ 2000

Let the percentage variation = x %

Or, x % increase = $\dfrac{\tyextrm new value - \textrm old value}{\textrm old value}$ × 100

Or, x % increase = $\dfrac{\tyextrm $ 2000 - \textrm $ 1500}{\textrm $ 1500}$ × 100

Or, x % increase = $\frac{500}{1500}$ × 100

Or, x % increase = $\frac{1}{3}$ × 100

Or, x % increase = $\frac{100}{3}$

∴ x = 33.3 %

So, The percentage increase change is 33.3 %

Hence The percentage change of vacationers is 33.3 % Answer

3 0

3 years ago