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Leto [7]
3 years ago
6

In the chemical equation H2O2(aq) → H2O(l) + O2( g., the O2( g. is a ____.

Chemistry
1 answer:
padilas [110]3 years ago
5 0
.......the answer is a gas
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You look for shells when you visit the beach. However, if you're hiking in the mountains and you find shells by accident, you kn
Lubov Fominskaja [6]

Answer:ThE aNsWeR iS B

Explanation: The earth was one a big ocean but than volcanoes explode and that created land :)

6 0
3 years ago
Read 2 more answers
1. How many grams of B are present in 3.35 grams of boron tribromide ?
Andre45 [30]

Answer:

The answer to your question is:

Explanation:

1. How many grams of B are present in 3.35 grams of boron tribromide ?

________ grams B.

MW BBr₃ = 251 g

                            251 g of BBr₃ ----------------------  11 g of B

                             3.35 g          -----------------------    x

                           x = (3.35 x 11) / 251 = 0.147 g of B

2. How many grams of boron tribromide contain 4.69 grams of Br ?

________grams boron tribromide.

MW BBr₃ = 251g

                             251g of BBr₃ -----------------   80 g of Br

                                   x               ----------------- 4.69 g

                           x = (4.69 x 251)/ 80 = 14.71 g of BBr₃

3. How many grams of N are present in 4.11 grams of nitrogen trifluoride ?

________grams N.

MW NF₃ = 71 g

                               71 g of NF₃    -----------------   14 g of N

                               4.11 g              ----------------     x

                               x = (4.11 x 14) / 71 = 0.81 g of N

4. How many grams of nitrogen trifluoride contain 3.07 grams of F ?

________grams nitrogen trifluoride.

MW NF₃ = 71

                                71 g of NF₃ ---------------------   19 g of F

                                  x               ---------------------   3.07 g

                                 x = (3.07 x 71) / 19 = 11.5 g of NF₃

5.How many grams of Co3+ are present in 1.16 grams of cobalt(III) iodide?

________grams Co3+.

MW CoI₃ = 440 g

                             440 g of CoI₃ ------------------  59 g of Co

                              1.16 g             ------------------   x

                              x = (1.16 x 59) / 440 = 0.16 g of Co

6. How many grams of cobalt(III) iodide contain 2.28 grams of Co3+?

________grams cobalt(III) iodide.

MW CoI₃ = 440 g

                             440 g of CoI₃ ------------------  59 g of Co

                               x                   -----------------   2.28 g of Co⁺³

                              x = (2.28 x 440) / 59

                              x = 17 g of CoI₃

5 0
3 years ago
How do i balance the first chemical reaction above?? plz plz help
soldier1979 [14.2K]

Answer:

2K +F₂→ 2KF

Explanation:

When we balance an equation, we are trying to ensure that the number of atoms of each element is the same on both sides of the arrow.

On the left side of the arrow, there is 1 K atom and 2 F atoms. On the right, there is 1 K and 1 F atom.

Since the number of K atoms is currently balanced, balance the number of F atoms.

K +F₂→ 2KF

Now, that the number of F atoms is balanced on both sides, check if the number of K atoms are balanced.

<u>Left</u>

K atoms: 1

F atoms: 2

<u>Right</u>

K atoms: 2

F atoms: 2

The number of K atoms is not balanced.

2K +F₂→ 2KF

<u>Left</u>

K atoms: 2

F atoms: 2

<u>Right</u>

K atoms: 2

F atoms: 2

The equation is now balanced.

4 0
3 years ago
A new process converts potential energy of an object to kinetic energy. Neither work nor eat is added to the system. No reaction
blagie [28]

Answer:

Change in height of the object

Explanation:

Change in height of the object

Since ,

We know potential energy can be written as mgh where

P.E. = mgh

M = mass ,

g = gravity constant

h = height

Kinetic energy can be written as 0.5 mv²

So , the Potential energy = kinetic energy

Then ,

velocity of object = √2 gh

Since g is a constant ,

Hence ,

Height of object will determine the velocity.

5 0
4 years ago
A student prepares a aqueous solution of trimethylacetic acid . Calculate the fraction of trimethylacetic acid that is in the di
irinina [24]

The question is incomplete, here is the complete question:

A student prepares a 0.21 mM aqueous solution of trimethylacetic acid. Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 3 significant digits.

<u>Answer:</u> The percent of dissociation of trimethylacetic acid is 19.5 %

<u>Explanation:</u>

We are given:

Concentration of trimethylacetic acid = 0.21 mM  = 0.00021 M    (Conversion factor:  1 mole = 1000 millimoles )

The chemical equation for the dissociation of trimethylacetic acid follows:

                     C_4H_9COOH\rightleftharpoons C_4H_9COO^-+H^+

<u>Initial:</u>                   0.00021

<u>At eqllm:</u>             0.00021-x              x            x

The expression of K_a for above equation follows:

K_a=\frac{[C_4H_9COO^-][H^+]}{[C_4H_9COOH]}

We know that:

K_a\text{ for }C_4H_9COOH=1\times 10^{-5}

Putting values in above expression, we get:

1\times 10^{-5}=\frac{x\times x}{(0.00021-x))}\\\\x=0.000041,-0.000051

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the fraction of dissociation, we use the equation:

\text{Percent of dissociation}=\frac{[H^+]}{[C_4H_9COOH]}\times 100

Putting values in above equation, we get:

\text{Percent of dissociation}=\frac{0.000041}{0.00021}\times 100\\\\\text{Percent of dissociation of trimethylacetic acid}=19.5%

Hence, the percent of dissociation of trimethylacetic acid is 19.5 %

8 0
3 years ago
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