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Answer:
6,04x10⁻³M
Explanation:
For the reaction:
Fe(s) + CuSO₄(aq) → Cu(s) + FeSO₄(aq)
The precipitate of Cu(s) weights 96,0 mg. In moles:
Moles of Cu(s):
0,096g×(1mol/63,546g) = 1,51x10⁻³ moles of Cu(s). If you see the balanced equation 1 mole of CuSO₄ produce 1 mole of Cu(s). That means moles of CuSO₄ are the same of Cu(s), <em>1,51x10⁻³ moles of CuSO₄</em>
As volume of the solution is 250 mL, 0,250L, the molar concentration of the original solution is:
1,51x10⁻³ moles of CuSO₄ / 0,250L = <em>6,04x10⁻³M</em>
I hope it helps!
Answer : The mass of arsenic present in 5.0 g of orpiment is, 1.5 grams.
Explanation : Given,
Mass of orpiment = 5.0 g
As we know that the molar mass of 
is, 246.02 g/mol and the molar mass of As is, 75 g/mol.
As per the question, we conclude that:
As, 246.02 g of contains mass of arsenic = 75 g
So, 5.0 g of contains mass of arsenic = 
Thus, the mass of arsenic present in 5.0 g of orpiment is, 1.5 grams.
Answer:
A and 3
B and 2
C and 1
Explanation:
<em>Ion</em>ic bonding is the transfer of electrons from a cat<em>ion</em> to an an<em>ion</em>.
Covalent bonding is the sharing of electrons between nonmetal atoms.
<em>Metallic</em> bonding is the sea of electrons <em>metal </em>cations.
Hope this helped!
