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aniked [119]
3 years ago
7

Explains WHY things behave the way they do - it is an explanation of a set of related observations or events based on a proven h

ypothesis and verified multiple times.
A.Law
B.Theory
C.Hypothesis
D.Question
Chemistry
1 answer:
Maslowich3 years ago
6 0
A. law
Because here’s the definition of law


laws of science are statements, based on repeated experiments or observations, that describe or predict a range of natural phenomena. The term law has diverse usage in many cases across all fields of natural science.
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Which type of front occurs when cold air and warm air are next to each other, but are at a standstill?
noname [10]
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8 0
3 years ago
Convert 150 kPa to atmospheres. *
lakkis [162]

Answer: 1.48 atmosphere

Explanation:

Pressure in kilopascal = 150

Pressure in atmosphere = ?

Recall that 1 atmosphere = 101.325 kilopascal

Hence, 1 atm = 101.325 kPa

Z atm = 150 kPa

To get the value of Z, cross multiply

150 kPa x 1 atm = 101.325 kPa x Z

150 kPa•atm = 101.325 kPa•Z

Divide both sides by 101.325 kPa

150 kPa•atm/101.325 kPa = 101.325 kPa•Z/101.325 kPa

1.48 atm = Z

Thus, 150 kPa is equivalent to 1.48 atmospheres

7 0
3 years ago
A scientist wrote down the steps to perform a chemical experiment, but they are out of order. Help the scientist by rearranging
ohaa [14]

Answer:

predict what's going to happen

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8 0
4 years ago
What is the purpose of a rain gauge?
FromTheMoon [43]
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7 0
3 years ago
Read 2 more answers
If you start with 100 grams of hydrogen-3, how many grams will you have after 24.6 years?
svet-max [94.6K]

Answer:

The mass left after 24.6 years is 25.0563 grams

Explanation:

The given parameters are;

The mass of the hydrogen-3 = 100 grams

The half life of hydrogen-3 which is also known as = 12.32 years

The formula for calculating half-life is given as follows;

N(t) = N_0 \times \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{\frac{1}{2} }} }

Where;

N(t) = The mass left after t years

N₀ =  The initial mass of the hydrogen-3 = 100 g

t = Time duration of the decay = 24.6 years

t_{\frac{1}{2} } = Half-life = 12.32 years

N(24.6) = 100 \times \left (\dfrac{1}{2} \right )^{\dfrac{24.6}{12.32}} } = 25.0563

The mass left after 24.6 years = 25.0563 grams.

4 0
3 years ago
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