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miv72 [106K]
3 years ago
13

How would show that lemon and tomato contains acids?

Chemistry
1 answer:
Vinvika [58]3 years ago
4 0
The acidity of any substance can be tested by a PH paper. 
There are also many chemical methods but these methods only tell you whether the substance is acidic, basic or neutral in nature.
Use Color code system along with PH paper,you can compare the colors and determine the exact acidity.

Note: Acid turns blue litmus paper to red. This is one of the tests for acidity.
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A block of ice is cooled from -0.5 degrees Celsius to -10.1 degrees Celsius. Calculate the temperature change, delta T, in degre
ss7ja [257]
Delta T= T final - T initial
Tfinal= -101.1 °C
Tinitial= -0.5 °C
•Delta T = -101.1°C - (-0.5°C)
=100.6°C

Kelvin= °C + 273
= -100.6 + 273
= 172.4 Kelvin
3 0
3 years ago
A metal melts at 450 degrees celsius. Is this property of the metal classified as chemical or physical?
Romashka-Z-Leto [24]
It's a physical property because it doesn't change the element of the metal.
does this make sense?
8 0
3 years ago
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maw [93]
Good job!!!!
Explanation: congratulations
7 0
3 years ago
Read 2 more answers
A clear colourless liquad that can be spilt into two gasses into different properties
Eduardwww [97]
Water can be split into O2 and H2 gas
7 0
3 years ago
3.47 g of the hydrated "double salt", ammonium iron (II) sulfate hexahydrate, FeSO4(NH4)2SO4*6H2O was dissolved in 200. mL of wa
Ostrovityanka [42]

Answer:

1.4 × 10^-4 M

Explanation:

The balanced redox reaction equation is shown below;

5Fe2+ + MnO4- + 8H+ --> 5Fe3+ +Mn2+ + 4H2O

Molar mass of FeSO4(NH4)2SO4*6H2O = 392 g/mol

Number of moles Fe^2+ in FeSO4(NH4)2SO4*6H2O = 3.47g/392g/mol = 8.85 × 10^-5 moles

Concentration of Fe^2+ = 8.85 × 10^-5 moles × 1000/200 = 4.425 × 10^-4 M

Let CA be concentration of Fe^2+ = 4.425 × 10^-4 M

Volume of Fe^2+ (VA)= 20.0 ml

Let the concentration of MnO4^- be CB (the unknown)

Volume of the MnO4^- (VB) = 12.6 ml

Let the number of moles of Fe^2+ be NA= 5 moles

Let the number of moles of MnO4^- be NB = 1 mole

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB= CAVANB/VBNA

CB= 4.425 × 10^-4 × 20 × 1/12.6 × 5

CB = 1.4 × 10^-4 M

7 0
3 years ago
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