Which means, per hour, the Car catches up by 55 - 50 = 5 miles
Since, the car starts AFTER the bus has already travelled 15 miles, the CAR IS BEHIND by 15 miles. To catch up these 15 miles (at the rate of catching up 5 miles per hour), the car would need:
15/5 = 3 hours to catch up with the BUS
<u>Note:</u> we use the formula
d = rt
where d = distance
r is rate
t is time
Thus, we had:
d = rt
t = d/r
t = 15/5
t = 3
Thus, after 3 hours, the car with catch up with the bus
(x+5)(x-5) , You use difference of two squares to do this. Remember that if the sign in the equation was (+) then you wouldn’t be able to continue factoring. You can only factor equations like these if there is a subtraction sign.