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melisa1 [442]
2 years ago
12

Write the equation of a line in slope intercept form that contains the points (0,2) and (3,4)

Mathematics
1 answer:
AlladinOne [14]2 years ago
6 0

Answer:

Step-by-step explanation:

Generally equation of a line is given as

y=mx+c

Then given the point (x, y)=(0,2)

Therefore x=0 and y=2

y=mx+c

2=m×0+c

2=0+c

Then, c=2

Then intercept is 2

Also given the point (x, y)=(3,4)

x=3 and y=4 and c=2

y=mx+c

4=m×3+2

4=3m+2

4-2=3m

2=3m

Then, m=2/3

Then, the slope of the graph is 2/3

y=mx+c

Now, m=2/3 and c=2

The general equation of the line becomes

y=2/3x+2

Multiply through by 3

3y=2x+6

Then this is the equation of the line

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2/6

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3 over 4 open parentheses 1 half x space minus space 12 close parentheses space plus space 4 over 5
lesantik [10]

For this case we have the following expression:

\frac {3} {4} (\frac {1} {2} x-12) + \frac {4} {5}

Rewriting the expression we have:

We apply distributive property to the terms of parentheses:

\frac {3} {8} x- \frac {36} {4} + \frac {4} {5}\\\frac {3} {8} x-9 + \frac {4} {5}\\\frac {3} {8} x- \frac {41} {5}\\

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\frac {3} {8} x- \frac {41} {5}

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2 years ago
2y=-x+9<br>3×-6y=-15 whats the solution to the system​
liq [111]

Answer:

Step-by-step explanation:

2y = -x +9

3x - 6y = -15

The solution is the value of x and y that will make the two equations true in the same time.

3x-6y = -15;  divide both sides by 3

x-2y = -5; substitute 2y for -x+9 because the first equation tell us they are equal

x-(-x+9) = -5; open parenthesis

x+x-9 = -5 ; add 9 to both sides  and combine like terms

2x = -5 +9; 2x = 4; divide both sides by 2

x= 2

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Solution is (2, 3.5)

8 0
2 years ago
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A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0
2 years ago
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