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sladkih [1.3K]
4 years ago
12

Solve the following equation showing all working:

Mathematics
2 answers:
larisa86 [58]4 years ago
8 0
Here is my solution. ask me if you need further explanation

const2013 [10]4 years ago
4 0
6a - 11 = 7
+11. +11
6a divided 18 = 3a
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Ella sold 37 necklaces for $20 each at the craft fair. She is going to donate half of the money she earned to charity. Use the C
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370 because 740 halved is 370

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I need a group of 4 functions and explain why they're functions.
Black_prince [1.1K]

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A group functions when everyone works together

5 0
3 years ago
PLEASE HELP ASAP AND IF YOU DONT KNOW DONT ANSWER (PHOTO ATTACHED)
Oxana [17]

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Step-by-step explanation:

8 0
3 years ago
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Assume that f(x)=ln(1+x) is the given function and that Pn represents the nth Taylor Polynomial centered at x=0. Find the least
WINSTONCH [101]

Answer:

the least integer for n is 2

Step-by-step explanation:

We are given;

f(x) = ln(1+x)

centered at x=0

Pn(0.2)

Error < 0.01

We will use the format;

[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01

So;

f(x) = ln(1+x)

First derivative: f'(x) = 1/(x + 1) < 0! = 1

2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1

3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2

4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6

This follows that;

Max|f^(n+1) (c)| < n!

Thus, error is;

(n!/(n + 1)!) × 0.2^(n + 1) < 0.01

This gives;

(1/(n + 1)) × 0.2^(n + 1) < 0.01

Let's try n = 1

(1/(1 + 1)) × 0.2^(1 + 1) = 0.02

This is greater than 0.01 and so it will not work.

Let's try n = 2

(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267

This is less than 0.01.

So,the least integer for n is 2

7 0
4 years ago
Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius . One day the high tempe
bazaltina [42]

The high temperature is 35 degree celsius

<em><u>Solution:</u></em>

Given that, Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius

Let "f" be the temperature in degree Fahrenheit

Let "c" be the temperature in degree celsius

Therefore,

Temperature in degrees Fahrenheit = 32 + \frac{9}{5} times the temperature in degrees Celsius

f = 32 + \frac{9}{5} \times c

One day the high temperature in Edison. Nj was 95 degrees Fahrenheit

f = 95 ; c = ?

Substitute f = 95 in above equation

95 = 32 + \frac{9c}{5}\\\\95=\frac{32 \times 5 +9c}{5}\\\\95 \times 5 = 160+9c\\\\475 = 160 + 9c\\\\9c = 475 - 160\\\\9c = 315\\\\c = 35

Thus high temperature in degrees Celsius is 35 degree celsius

5 0
3 years ago
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