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gogolik [260]
3 years ago
12

= -6x + 8(x + 2)" alt="-2(3 - 2x) = -6x + 8(x + 2)" align="absmiddle" class="latex-formula">
solve step by step​
Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{x = 11}}}}}

Step-by-step explanation:

\sf{ - 2(3 - 2x) =  - 6x + 8(x + 2)}

Distribute -2 through the parentheses

Similarly, Distribute 8 through the parentheses

\dashrightarrow{ \sf{ - 6 + 4x =  - 6x + 8x + 16}}

Collect like terms

\dashrightarrow{ \sf{ - 6 + 4x = 2x + 16}}

Move 2x to left hand side and change it's sign

Similarly, move 6 to right hand side and change it's sign

\dashrightarrow{ \sf{4x - 2x = 16 + 6}}

Collect like terms

\dashrightarrow{ \sf{2x = 16 + 6}}

Add the numbers : 16 and 6

\dashrightarrow{ \sf{2x = 22}}

Divide both sides by 2

\dashrightarrow{ \sf{ \frac{2x}{2}  =  \frac{22}{2} }}

Calculate

\dashrightarrow{ \sf{x = 11}}

Hope I helped!

Best regards! :D

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Read 2 more answers
Graph the line y=-3x-2
sashaice [31]

Answer:

The graph of the line is attached below.

Step-by-step explanation:

According to the slope-intercept form

y=mx+b

As the line equation  is given by

y=\:-3x\:-\:2\\

\mathrm{Slope\:of\:}-3x-2:\quad m=-3

y-intercept = b = -2

\mathrm{Axis\:interception\:points\:of}\:-3x-2:\quad \mathrm{X\:Intercepts}:\:\left(-\frac{2}{3},\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-2\right)

  • \mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0

-3x-2=0:\quad x=-\frac{2}{3}

\mathrm{X\:Intercepts}:\:\left(-\frac{2}{3},\:0\right)

  • y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0

y=-3\cdot \:0-2:\quad y=-2\\

\mathrm{Y\:Intercepts}:\:\left(0,\:-2\right)

The graph of the line is attached below.

7 0
3 years ago
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