Answer:
21. r; 2.83 d; 5.66
22. d; 13.4 c; 42.09
23. r; 5.3 c; 33.30
24. r; 0.49 d; 0.99
Step-by-step explanation:
Hope this helps ;)
The perpendicular bisector would be the line that connects with the line HI at a 90 degree angle and in the mid-point. This means that we would have to find the slope of the line HI and take the opposite. The slope of HI is 1/3. This means that the slope of the perpendicular line is -3. Now we must solve for the line that crosses through the midpoint. y=mx+b we know that m=-3 and that the midpoint is at -1,3 so x=-1 and y=3. 3=(-3)-1+b. We then solve for b and find it to be 0. So the final answer is y= -3x
Answer:
The correct option is;
∠AQS ≅ ∠BQS when AS = BS
Step-by-step explanation:
Given that AQ is equal to BQ. When AS is drawn congruent to BS, we have;
QS is congruent to SQ by reflective property
Therefore;
The three sides of triangle QAS are congruent to the three sides of triangle QBS, from which we have;
∠AQS and ∠BQS are corresponding angles, therefore;
∠AQS ≅∠BQS because corresponding angles of congruent triangles are also congruent.