How would you graph the equation above y=3x+3 on a coordinate plane?
1 answer:
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Answer:
1 and 6
Step-by-step explanation:
it is just like the roots of a polynomial, since (x-6)^2=0
we can separate the two pieces of the problem
\sqrt{x-1} =0
square both sides to get
x-1=0. x=1
(x-6)^2=0
square root both sides and get
x-6=0
x=6
so the two inflection points of the equation are 6 and 1
Hope that helps :)