The following list gives the number of public libraries in each of 11 cities. 7, 11, 8, 7, 8, 7, 8, 11, 8, 10, 7 Find the modes
AlladinOne [14]
Answer:
The mode are: 7, 8
Step-by-step explanation:
Given

Required
Determine the mode
We start by arranging the given data in ascending order
The ordered data are:

From the above data.
7 has a frequency of 4
8 has a frequency of 4
10 has a frequency of 1
11 has a frequency of 2
The data with the highest frequency is the mode.
We can see that 7 and 8 both have frequencies of 4
<em>Hence, the mode are: 7, 8</em>
In an installment loan, a lender loans a borrower a principal amount P, on which the borrower will pay a yearly interest rate of i (as a fraction, e.g. a rate of 6% would correspond to i=0.06) for n years. The borrower pays a fixed amount M to the lender q times per year. At the end of the n years, the last payment by the borrower pays off the loan.
After k payments, the amount A still owed is
<span>A = P(1+[i/q])k - Mq([1+(i/q)]k-1)/i,
= (P-Mq/i)(1+[i/q])k + Mq/i.
</span>The amount of the fixed payment is determined by<span>M = Pi/[q(1-[1+(i/q)]-nq)].
</span>The amount of principal that can be paid off in n years is<span>P = M(1-[1+(i/q)]-nq)q/i.
</span>The number of years needed to pay off the loan isn = -log(1-[Pi/(Mq)])/(q log[1+(i/q)]).
The total amount paid by the borrower is Mnq, and the total amount of interest paid is<span>I = Mnq - P.</span>
Answer:
1:
p-r/6=-6-(-6)/6=-6+1=<u>-</u><u>5</u>
<u>2</u><u>:</u>
<u>p-</u><u>(</u><u>m-n</u><u>)</u><u>=</u> -1-(-4-4)=-1-(-8)=-1+8=<u>7</u>
3:
(z+y)/2)3=(-5-4)/3=-9/3=<u>-</u><u>3</u>
<u>4</u><u>:</u>
m/6-n=6/6-6=1-6=<u>-</u><u>5</u>
5:
k³-h=3³-(-2)=27+2=<u>2</u><u>9</u>
6:
p-(p-(m-3))=5-(5-(4-3))=5-(5-1)=5-4=<u>1</u>
7:
(k)(k-j)+3=(5)(5-5)+3=5*0+3=<u>3</u>
8.
p²/6-q=6²/6-4=6-4=<u>2</u>
<u>9</u><u>;</u>
zx+3³=6*4+3³=24+27=<u>5</u><u>1</u><u>.</u>
<u>1</u><u>0</u><u>:</u>
<u>y</u><u>+</u><u>z</u><u>-</u><u>(</u><u>y</u><u>-</u><u>x</u><u>)</u><u>=</u>5+4-(5-2)=9-3=<u>6</u>
<u>S</u><u>o</u><u>m</u><u>e</u><u> </u><u>b</u><u>a</u><u>s</u><u>i</u><u>c</u><u> </u><u>r</u><u>u</u><u>l</u><u>e</u><u>s</u><u>:</u>
+. +. +=+
+. * +=+
+. ÷ +=+
+. - +=+
and
+. +. -=add and put sigh of greater one.
-. * +=-sigh
-÷-=+sigh
- - -=add and put - sigh
The sum of two numbers is 136 (sum is what you get when you add two numbers together). If one of the two numbers is 51, and the other number is X, then:
X + 51 = 136
To solve for x we subtract both sides by 51.
X + 51 -51 = 136 - 51
X = 85
The other number is 85.
What are the common factors of these two numbers?
Factors are the numbers that multiply to make the product.
Factors of 51: 1, 51, 3, 17
Factors of 85: 1, 85, 5, 17
Take the length as 'x'
Width = 2x - 2
Perimeter = 44 [ Formula = 2(l + w) ]
2 (l + w) = 44
2 (x + 2x - 2) = 44
2 (3x - 2) = 44
6x - 4 = 44
6x = 44 + 4
6x = 48
x = 48/6
<u>x </u><u>=</u><u> </u><u>8</u> => length
Width = 2x - 2 = 2(8) - 2 = <u>1</u><u>4</u><u> </u><u>units.</u>
Hope it helps!
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