Question

Diners at a certain restaurant can choose either a soup or salad from 4 choices, an entree from 5 offerings, two side dishes from 5 options, and, finally, one of 4 dessert cakes. To the nearest whole number, how many months could a person eat at this restaurant without having to order the same meal twice? (Assume 30 days per month.)
A) 20B) 27C) 63D) 160E) 800

Answer 1

Answer:

Answer is - B) 27

Step-by-step explanation:

Total choices can be found as :

Either a soup or salad from 4 choices : 4

An entree from 5 offerings : 5

Two side dishes from 5 options : 5C2 = $\frac{5\times4\times3\times2\times1}{2\times1\times3\times2\times1}$

= 10

One of 4 dessert cakes : 4

So, total choices become : $4\times5\times10\times4=800$

And given there are 30 days in the month, so it becomes:

$\frac{800}{30}= 26.67$ ≈ 27