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11 months ago

Can someone pls help me on question 8) plss thank you!! I will give a brainstar Question 8!!

Mathematics

1 answer:

Korolek [52]11 months ago

6 0

Answer:

$226

Step-by-step explanation:

1. define the variable x

x = # of days to rent the carpet cleaner

2. substitute x for 7 days

c(7) = 30(7) + 16

3. solve

c(7) = 210 + 16

c(7) = 226

For 7 days, Rhonda will have to rent the carpet cleaner for $226.

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If f(x) =2x+3 then the point (1,5) is on the graph of f true or false

ss7ja [257]

F(x)=y=2x+3
P (1,5)
Substitute x and y:
5=2*(1)+3
5=5 true
Point P (1,5) is on the graph of f.

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3 years ago

1 saa<br> ite<br> 5. Count by tens. What is the<br> next number?<br> 20, 30, 40, 50,

OleMash [197]

Answer:

Step-by-step explanation:

I would assume you want the answer step-by-step:

We can count carefully and read the question again.

It is asking for us to count by tens or add ten to the most recent integer in the pattern.

In that case, we can see that our answer will by 50 + 10 = 60.

Also, note, that this question is not very intellectually challenging! Next time ask a question like "What do they mean when they say this?" If you don't understand the wording.

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2 years ago

Read 2 more answers

What is 43,000 in scientific notation?

ki77a [65]

43,000 in scientific notation is 4.3 x 10^4

6 0

2 years ago

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

2 years ago

Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are .

Evgen [1.6K]

QUESTION 1

The point C(3.6, -0.4) divides AB in the ratio 3 : 2.

The coordinates of A are (-6, 5).

Let the coordinates of B be $(x_2,y_2)$

We use the formula:

$x=\frac{mx_2+nx_1}{m+n}$ to determine the x-coordinate of B.

We substitute the known values to obtain:

$3.6=\frac{3x_2+2(-6)}{3+2}$

$3.6=\frac{3x_2-12)}{5}$

$3.6\times 5=3x_2-12$

$18=3x_2-12$

$18+12=3x_2$

$30=3x_2$

This implies that:

$x_2=10$

We also use the formula:

$y=\frac{my_2+ny_1}{m+n}$ to find the y-coordinate.

$-0.4=\frac{3y_2+2(5)}{3+2}$

$-0.4=\frac{3y_2+10}{5}$

$-0.4\times 5=3y_2+10$

$-2-10=3y_2$

$-12=3y_2$

$-4=y_2$

The coordinates of B are (10,-4)

QUESTION 2.

If point D divides CD in the ratio 4 : 5.

Then the coordinates of D are:

$(\frac{4(10)+5(3.6)}{4+5}, \frac{4(-4)+5(-0.4)}{4+5})$

$(\frac{58}{9}, \frac{-18}{9})$

The coordinates of D are $(\frac{58}{9}, -2)$

8 0

3 years ago