The product of the sum of two perfect cubes:
a³ + b³ = (a + b)(a² - ab + b²)
The product of the difference of two perfect cubes:
a³ - b³ = (a - b)(a² + ab + b²)
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Remember to follow FOIL:
(b^2 + 8)(b^2 - 8)
(b^2)(b^2) = b^4
(b^2)(-8) = -8b^2
(8)(b^2) = 8b^2
(8)(-8) = -64
b^4 - 8b^2 + 8b^2 - 64
Combine like terms:
b^4 (-8b^2 + 8b^2) - 64
b^4 - 64
b^4 - 64 is your answer
hope this helps
I believe,the answer is c
<h2>Steps</h2>
So to find the solutions, I will be factoring by grouping. Firstly, what two terms have a product of 12x² and a sum of -8x? That would be -2x and -6x. Replace -8x with -2x - 6x:

Next, factor 4x² - 2x and -6x + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite it as:

Now, apply the zero product property and solve:

<h2>Answer</h2>
<u>In short, x = 3/2 (1.5) and 1/2 (0.5).</u>
Answer:

Step-by-step explanation:
We have been given that a hockey goalie loses 2 3/5 rating points each time his team loses. His team loses 8 games in a row.
To find the number that will represent the change in goalie's ratings after losing 8 games we will multiply 8 by
.
Let us convert our mixed fraction into improper fraction.



Therefore,
will represent the change in the goalie's rating points.