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aniked [119]
3 years ago
10

Maggie buys 5 apples and 4 oranges for $10 and Lynn buys 5 apples and 5 oranges for $11. What is the price for an apple and what

is the price for an orange?
Mathematics
1 answer:
nlexa [21]3 years ago
6 0
Make 2 eqn, let a be apples and o be oranges:

1. 5a + 4o = 10
2. 5a + 5o = 11

set up an elimination:
1. minus 2.
5a + 4o = 10
- 5a + 5o = 11
____________
o = 1

sub “o” into one of the eqn

5a + 5(1) = 11
5a = 11-5
5a = 6
a = 6/5
a = 1.2

therefore, an orange costs $1.00 and an apple costs $1.20

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3 years ago
Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what
professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 64, \sigma = 1.5

What percentage of women are between 65.5 inches and 68.5 inches?

This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.

X = 68.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{68.5 - 64}{1.5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 65.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{65.5 - 64}{1.5}

Z = 1

Z = 1 has a pvalue of 0.8413

So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.

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