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Zanzabum
3 years ago
8

What equation represent 3x3/5 as a multiple of a unit fraction

Mathematics
1 answer:
Agata [3.3K]3 years ago
4 0
The answer is 9/5 as 3×3 is 9 and you are dividing it by 5.
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Please give an explanation with you answer, thank you :)
Genrish500 [490]
f(x)=2( \sqrt[3]{27})^{2x}

Here 2 on left most side is the coefficient, 2x is the exponent and the of the function is cube root of 27.

So,

Base= \sqrt[3]{27}  \\  \\ 
Base= \sqrt[3]{3^{3} } \\  \\ 
Base=3

Thus, the simplified base for the function is 3. So correct answer is option  B
4 0
4 years ago
Round of 94136 to the nearest whole number
marta [7]

Answer:

94136

Step-by-step explanation:

It would just be the same thing because their is no decimal or fraction after the number and 94136 is already a whole number

3 0
3 years ago
um pai tem hoje 54 anos e seus quatro filhos tem juntos 39 anos. dentro de quantos anos a idade do pai será a soma da idade dos
Elan Coil [88]

a1 + r.N = b1 + R.N  

54 + 1.N = 39 + 4.N  

4.N - 1.N = 54 - 39  

3.N = 15  

N = 15 / 3  

N = 5 anos

8 0
3 years ago
If 4^2x+1 = 4, then =
Aneli [31]

Step-by-step explanation:

step 1. what is the question? probably solve for x. okay.

step 2. 4^(2x) + 1 = 4

step 3. 4^(2x) = 3 subtract 1 from each side

step 4. ln4^(2x) = ln3 take on of each side

step 5. 2xln4 = ln3 definition of logs

step 6. 2x = ln3/ln4 divide both sides by ln4

step 7. x = ln3/2ln2^2 divide both side by 2 and replace 4 with 2^2

step 8. x = ln3/4ln2.

4 0
3 years ago
The volume of a fish tank is 60 cubic feet. If the density is 0.3 fish over feet cubed, how many fish are in the tank? 200 9 100
FinnZ [79.3K]

Answer:

There are 18 fish in the fish tank.

Step-by-step explanation:

The volume of a fish tank is 60 cubic feet: V = 60 ft³.

The density is 0.3 fish over feet cubed. d = 0.3 fish/ft³

We can find the number of fish using proportions. The required conversion factor is 0.3 fish/ft³. The number of fish is:

60 ft³ × (0.3 fish/ft³) = 18 fish

There are 18 fish in the fish tank.

5 0
3 years ago
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