In fission processes, which of the following statements is true? The total number of protons and the total number of neutrons bo
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Gravitational force on a satellite is given by the formula
now here we know that force on the satellite is F when its distance from center of Earth is R
Now the distance from the center of earth will be 3R so the force is given as
so if we compare it with initial value of force then it is
so correct answer is
The angular velocity depends on the length of the orbit and the orbital
speed of the telescope.
Response:
First question:
- The angular velocity of the telescope is approximately <u>0.199 rad/s</u>
Second question:
- The telescope should accelerates away by approximately F = <u>0.0005·m </u>
Third question:
- <u>The pulling force between the Earth and the satellite</u>
The distance of the James Webb telescope from the Sun = 1.5 million kilometers from Earth on the side facing away from the Sun
The orbital velocity of the telescope = The Earth's orbital velocity
First question:
The orbital velocity of the Earth = 29.8 km/s
The distance between the Earth and the Sun = 148.27 million km
The radius of the orbit of the telescope = 148.27 + 1.5 = 149.77
Radius of the orbit, r = 149.77 million kilometer from the Sun
The length of the orbit of the James Webb telescope = 2 × π × r
Which gives;
r = 2 × π × 149.77 million kilometers ≈ 941.03 million kilometers
Therefore;
- The angular velocity of the telescope, ω ≈ <u>0.199 rad/s</u>
Second question:
Centrifugal force force, = m·ω²·r
Which gives;
Universal gravitational constant, G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²
Mass of the Sun = 1.989 × 10³⁰ kg
Which gives;
Which gives;
<
, therefore, the James Webb telescope has to accelerate away from the Sun
F = -
The amount by which the telescope accelerates away is approximately 0.00592·m - 0.0054233·m ≈ <u>0.0005·m (away from the Sun)</u>
Third part:
Other forces include;
- <u>The force of attraction between the Earth and the telescope </u>which can contribute to the the telescope having a stable orbit at the given speed.
Learn more about orbital motion here: