Answer: No, x+3 is not a factor of 2x^2-2x-12
========================================================
Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
----------------------------------------
Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
Answer: 6/13
Step-by-step explanation: a/a+b = 6/6+7 = 6/13
Answer:
any point on the graph that's not shaded
Step-by-step explanation:
you can just plot any point on the graph that's not shaded(because it's not a solution to the inequality).
for example, (3, -5) or (-4, -5) or (7, 0)
Answer:
-40, - 42 and -44
Step-by-step explanation:
The fastes way here is trying. Lets pick a number, intelligently, and then work on it.
We need three even integers that sum -126. These will be all negative numbers and as they are consecutive they will be very similar (for example, -33 and -35 and -37). Thus, lets start by 1/3 of -126, which is -42:
(-42)+ (-44) + (-46) = - 132, so -42 no.
Lets go a step back: -40
(-40) + (-42) + (-44) = -126
So, the integers are -40, -42 and -44
Answer:
50:39
Step-by-step explanation:
The first number in the context always goes first!
